Component\Main\Source\Rating\Source\Rating.Domain\Services\OrderRatingQueueService.cs:line 52
at Benchmarking.Program.OrderRatingQueue() in C:\DevProjects\Component\Main\Source\Benchmarking\Source\Benchmarking\Program.cs:line 81at Benchmarking.Program.Main(
result += String.format("%4d", randomArray);
return result;
public class Benchmarkingat java.util.Formatter.format(Formatter.java:2455)at Benchmarking.methods.getArray(methods.java:68)
at Benc
我为Haskell的内置exists列表数据类型编写了量化函数forall和none。在许多情况下,这似乎比Prelude/Data.List的any和all有效得多。我天真地怀疑,这种性能是由于any和all使用Θ(n)折叠实现的。因为我对哈斯克尔比较陌生,我想我一定是弄错了,否则会有一个很好的理由造成这种现象。-- | Determines whether any element of the structure satisfies the predicate.
any :: Foldable t => (a -> Bool) -> t