C中的链表，返回一个void函数的指针

#include <stdio.h>
#include <stdlib.h>

// 定义链表节点结构
struct Node {
    int data;
    struct Node* next;
};

// 创建链表并返回头节点指针
void* createLinkedList() {
    struct Node* head = NULL;
    struct Node* second = NULL;
    struct Node* third = NULL;

    // 分配内存并设置节点数据
    head = (struct Node*)malloc(sizeof(struct Node));
    second = (struct Node*)malloc(sizeof(struct Node));
    third = (struct Node*)malloc(sizeof(struct Node));

    head->data = 1;
    head->next = second;

    second->data = 2;
    second->next = third;

    third->data = 3;
    third->next = NULL;

    return head;
}

int main() {
    // 创建链表并获取头节点指针
    struct Node* head = (struct Node*)createLinkedList();

    // 遍历链表并打印节点数据
    struct Node* current = head;
    while (current != NULL) {
        printf("%d ", current->data);
        current = current->next;
    }

    return 0;
}