以下是查询:select charindex(char(0), substring(AddressTail, 17, 1)) from Address where ID = 1934484返回预期的1select charindex(char(0), AddressTail) from Address where ID = 1934484返回
SELECT CHARINDEX('space and /* comment */', 'Phrase with space and /* comment */') AS MatchPosition;DECLARE @SearchWord varchar = 'space and /* comment */'
SELECT CHARINDEX(@SearchWord, 'Phrase with spaceand /*
我是java的新手,我正在尝试创建一个程序来测试用户两个随机频率之间的差异。除了当我试图得到2个频率的差值时,答案总是0之外,一切都是有效的。如何让它显示实际的差异?下面是我用来创建音调和计算差值的类: private PitchPlay two = new PitchPlay();
private int frequencyTwo;
private int dif = new