我有读取pom.xml文件的代码,然后尝试重新序列化并将其写回:
// Get the file raw text
def pomXMLText = readFile(pomFile)
// Parse the pom.xml file
def project = new XmlSlurper(false, false).parseText(pomXMLText)
... do some useful stuff ...
def pomFileOut = "$WORKSPACE/pomtest.xml"
def pomXMLTextOut = groovy.xml.
我正在使用groovy的修改xml文件,并使用groovy的将其写回。
def xml = new XmlSlurper(false,false).parseText(new File("pom.xml").text)
// Append new elements or nodes
xml.appendNode {
pluginRepositories {
pluginRepository {
id 'synergian-repo'
url 'https://raw.github.
我转义一个字符串以匹配另一个字符串。
使用javascript
function escapeCode()
{
var a = RequestIsland.XMLDocument.firstChild;
var lineItems = a.selectNodes( "//a/p" );
while ( (lineItem = lineItems.nextNode()) != null )
{
var text = lineItem.getAttribute("c");
alert
我有一些用XmlSlurper解析的xml,我想添加一个新节点,然后引用这个新节点。这演示了我正在尝试做的事情。除了1.添加节点2.序列化3.再次解析4.引用新节点?
import groovy.xml.XmlUtil
def xml = new XmlSlurper().parseText("<foo/>")
xml.appendNode({bar()});
//now try to append something to bar. Probably doesn't work because it's a closure
xml.bar.app
在运行gradle构建(使用gradle 6.8.3)时,我们得到:
> Configure project :buildSrc
The Project.libsDir property has been deprecated. This is scheduled to be removed in Gradle 7.0. Please use the libsDirectory property instead. See https://docs.gradle.org/6.8.3/dsl/org.gradle.api.Project.html#org.gradle.api.Project
我有一个对象,看起来像这样:
public MyObject
{
public int ObjectID {get;set;}
public byte ObjectStatus {get;set;}
public List<MySubObject1> {get;set}
public List<MySubObject2> {get;set}
...
public List<MySubObject9> {get;set}
public string MySubObject1InJson {get;set;}
...
pub