我有以下查询。
SELECT (
SELECT
COUNT (fibre_circuit.data_id)
FROM fibre_circuit
INNER JOIN bus_std_iptv
ON bus_std_iptv.d_parent_id = fibre_circuit.data_id
where fibre_circuit.data_id = 778
) AS Count1,
(
SELECT
COUNT (fibre_circuit.data_id)
FROM f
我需要在find first match之后退出循环,并在循环中进行另一次搜索
use strict;
use warnings;
my %iptv;
sub trim($) {
my $string = shift;
$string =~ s/\r\n//g;
$string =~ s/^\s+//;
$string =~ s/\s+$//;
return $string;
my @files=</tests/*>;
open IN, "/20131105.csv";
LINE: while (&l
我试图为我的网站创建一个下钻菜单,用户将点击一个类别,它将显示被点击的类别的子类别,可能有n个级别。我能够写sql查询,这返回的输出完全如我所希望的,但问题是…我不想显示整个菜单给最终用户,我想打开/展开只点击类别。
my Query output is:
1 IPTV
2 Jadoo Tv
3 Shava Tv
4 Jalva Tv
5 Programming
6 Microsoft
7 Asp.Net
8 PHP
因此,默认情况下,应该显示IPTV和节目,因为它们是父母,当我点击IPTV时,它应该会打开IPTV
我有这样的数据
mis mnth IPTV
------------------------------------
0 January 0.2026856
0 February 0.4860267
0 March 0.2650674
0 April 0.1904701
1 January 0.266809
1 February 0.310241
1
我的输入文件如下所示:
#EXTM3U
#EXTI NF:-1 tvg-name="Das Erste HD" tvg-id="ARD.de" group-title="Vollprogramm" tvg-logo="https://raw.githubusercontent.com/jnk22/kodinerds-iptv/master/logos/tv/daserstehd.png",Das Erste HD
https://daserstehdde-lh.akamaihd.net/i/daserstehd_de@625196
我有一个打印函数的原始输出,如下所示: b'\r\nsw-dektec#\r\nsw-dektec#terminal length 0\r\nsw-dektec#sh mvr members\r\nMVR Group IP Status Member Membership \r\n-------------------------------------------------------------\r\n232.235.000.001 ACTIVE/UP Gi1/0/21 Dynamic \r\
List<Data> datas = [];
Future<List<Data>> getData() async {
final response =
await http.get('https://iptv-org.github.io/iptv/index.country.m3u');
final m3u = await M3uParser.parse(response.body);
for (final entry in m3u) {
Data data = Data(entry.title, entry.attributes