我是SQL的新手,我想要一些关于这个查询的帮助。这是到目前为止我的脚本。如果你需要更多信息,请告诉我,
SELECT DISTINCT EstimName_String AS Inspector, InspectionProcedureName AS [Inspection Procedure Name], COUNT(*) AS InspectionsDone
FROM UnitData_Vehicle
WHERE (InspectionProcedureName LIKE '%Inspection%')
where datediff(
我有一个输入文本框,让最终用户填写他们执行检查的日期。当通过表单提交存储在数据库中时,我希望格式化为MM/DD/YYYY的日期。
我尝试过使用preg_match函数对其进行regex检查,但对于否则命令或if命令,我有一些不太正确的地方。它仍然允许04-05-2019提交,而不是停止提交。任何帮助都将不胜感激!
//check inspection date format with regex
$date_check_regex = "/(0[1-9]|1[012])[- \/.](0[1-9]|[12][0-9]|3[01])[-
\/.](19|20)\d\d/";
我有一套关于面包车的记录(序列号、作业号、作业类型和当前里程)。
select serial_number, call_ref, call_type_description, callm_data19
from calls
left join equipment on link_to_equipment=equipment_code
inner join lu_call_types on call_type=call_type_code
left join call_more on call_ref=callm_link_to_call
where serial_number = 'S
有没有办法对SSRS报告的URL进行编码?
我尝试了以下方法,但输出与我需要的不匹配:
代码:
System.Uri.EscapeUriString("Receiving Inspection/Receiving Inspection End Of Lot")
结果:
Receiving%20Inspection/Receiving%20Inspection%20End%20Of%20Lot
我也试过..。
代码:
System.Uri.EscapeDataString("Receiving Inspection/Receiving Inspection End Of
我有一个select语句,其中包含一个用Oracle编写的dense_rank函数,但是我在弄清楚如何使它与postgressql (v11.x)兼容时遇到了麻烦。 SELECT facility_id_fk, max(inspection_date) as last_inspection,
max(inspection_type) keep (dense_rank first order by inspection_date desc) as inspection_type
FROM facility_inspections
GROUP BY facility
我有这样的疑问:
SELECT a.ID_ITEM_INSPECTION, a.NOMOR_ITEM_INSPECTION, a.NAMA_ITEM_INSPECTION,
(SELECT d.NO_INSPECTION FROM tb_master_inspection_report d WHERE d.NO_INSPECTION = 66) AS NO_INSPECTION,
b.ID_ITEM_INSPECTION, b.CONDITION, b.PCS, b.`ALIAS`
FROM `db_depo`.`tb_item_inspection_report` a
LEFT JOI
它的角度4很好,现在我升级到5.0。现在我得到了以下错误。整个项目(角4)在github中。
ERROR in src/app/lineside-inspection/lineside-inspection.service.ts(44,9): error TS2322: Type 'Promise<void | LineSideInspection>' is not assigna
ble to type 'Promise<LineSideInspection>'.
Type 'void | LineSideInspectio
我有三张桌子。
检查(A)
Inspection_Vehicle (B)
Inspection_Vehicle_Defect (C)
当C中的所有链接行的a值为6的Checklist_Result_ID列中时,我希望返回A中的所有行
表C包含链接到表B- Inspection_Vehicle_ID的列,表B包含链接到表A- Inspection_ID的列.
我想做这样的事:
SELECT DISTINCT A.* FROM Inspection AS A
LEFT JOIN Inspection_Vehicle AS B ON B.Inspection_ID = A.Ins
假设我们有一个连接表vehicle_inspections和另一个连接表inspection_actions,以及actions,vehicles, and检查的基本表。
让我说,我希望获得以下DB条目:
vehicles
----------------------------
id make
----------------------------
1 Toyota
actions
-------------------------------
id description
----------------------------
我有一个非常简单的关系设置,我无法让odb输出编译,它给了我下面的编译器错误。我正在使用Qt智能指针来实现这种关系,无论我经历了多少排列,我似乎总是遇到相同的错误。
/usr/local/include/odb/database.ixx:570:54: error: no matching function for call to ‘odb::object_traits_impl<Inspection, (odb::database_id)1u>::find(odb::database&, const id_type&)’
下面是父类
#ifndef PART_H
$(document).on('click', '.bg-maroon', function () {
var id = $(this).val();
$.ajax({
url: "<?= base_url('surveyor/c_surveyor_inspection/get_data_untuk_inspection_surveyor_dua'); ?>",
type: "POST",
dat
我在Windows上运行了一个运行Server的现有应用程序,并且正在使用C#语言的内联查询。这是我在Management中正确工作的查询:
command = @"SELECT
P_InspectionStep.InspectionStepID,
P_InspectionStep.Sequence AS Sequence,
P_InspectionStep.Title AS Title,
P_InspectionStep.Body AS Body,
我是iOS的新手,我面临着在数组中获取字典的问题。
数组如下所示:
[{"CheckPointId":41,"AId":4,"CheckPoint":"Check SOP maintained near all equipments and loads","MId":41,"MethodOfMeasure":"Visual Inspection"},{"CheckPointId":42,"AId":4,"CheckPoint":"
我正在尝试保存一条记录,然后获取新创建的objectId.我使用以下代码。
var query = new Parse.Query("Inspection");
var Inspection = new Parse.Object("Inspection");
query.include('property');
query.equalTo("property", { "__type": "Pointer", "className"
我正在张贴值,但我得到的是空数组。我知道它的节点异步问题。但我不知道该怎么解决这个问题。我有以下链接:
但我无法理解。请帮助我理解承诺,以及如何在代码中使用这些承诺。
router.post('/inspection_list', function (req, res) {
var id = req.body.project_id;
console.log(id)
// res.send("ok")
db.inspection.findOne({'_id':id},(err,response)=>{
我每1秒执行一次查询,大部分时间它不返回结果(实体框架生成的SQL):
SELECT TOP (5)
[Extent1].[ID] AS [ID],
***30 more columns***
FROM ParentTable AS [Extent1]
WHERE ([Extent1].[ImageTaken] = 1) AND ([Extent1].[ImageProjected] <> 1) AND ( EXISTS (SELECT
1 AS [C1]
FROM ChildTable AS [Extent2]
W
我的数据库里有很多数据。我正在使用Mysql。
在这个例子中,我尝试使用一些查询来显示第三周的数据:
SELECT Line, (SUM(S) + SUM(A) + SUM(B)*0.4 + SUM(C)*0.1)/COUNT(Serial_number) AS 3rd
FROM inspection_report
WHERE DAY(Inspection_datetime) BETWEEN 15 AND 21
GROUP BY Line, WEEK(Inspection_datetime), YEAR(Inspection_datetime)
但结果显示为:
line coun
我正在尝试创建这个函数,但是空值失败。
CREATE OR REPLACE function func(inspection_date date, strike_time date, taskaction_display varchar, last_known_status varchar, severity int)
RETURNS TABLE(last_known_task_status varchar, taskaction int) AS $$
SELECT CASE
WHEN inspection_date IS null THEN (taskaction_d
我正在使用Roo从Rails应用程序中输出一个电子表格。我的一列是散列(Postgres )。我想将单元格内容格式化为更具可读性的内容。我正在使用一种方法返回人类可读的单元格。
列数据如下所示:
Inspection.first.results
=> {"soiled"=>"oil on back",
"assigned_to"=>"Warehouse@firedatasolutions.com",
"contaminated"=>"blood on left cuff",