Java如何对Point对象的ArrayList进行排序

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

public class Main {
    public static void main(String[] args) {
        ArrayList<Point> points = new ArrayList<>();
        points.add(new Point(3, 4));
        points.add(new Point(1, 2));
        points.add(new Point(5, 1));

        // 使用默认的自然排序顺序进行排序
        Collections.sort(points);

        // 输出排序后的结果
        for (Point point : points) {
            System.out.println(point);
        }
    }
}

class Point implements Comparable<Point> {
    private int x;
    private int y;

    public Point(int x, int y) {
        this.x = x;
        this.y = y;
    }

    public int getX() {
        return x;
    }

    public int getY() {
        return y;
    }

    @Override
    public int compareTo(Point other) {
        // 按照x坐标进行排序
        if (this.x < other.x) {
            return -1;
        } else if (this.x > other.x) {
            return 1;
        } else {
            // 如果x坐标相同，则按照y坐标进行排序
            if (this.y < other.y) {
                return -1;
            } else if (this.y > other.y) {
                return 1;
            } else {
                return 0;
            }
        }
    }

    @Override
    public String toString() {
        return "(" + x + ", " + y + ")";
    }
}