Java读取200万行文本文件的最快方法

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;

public class FastFileReader {
    public static void main(String[] args) {
        String filePath = "path/to/your/file.txt";
        try (BufferedReader br = new BufferedReader(new FileReader(filePath))) {
            String line;
            while ((line = br.readLine()) != null) {
                // 处理每一行数据
                processLine(line);
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private static void processLine(String line) {
        // 处理每一行的逻辑
        System.out.println(line);
    }
}

import java.io.IOException;
import java.nio.ByteBuffer;
import java.nio.channels.FileChannel;
import java.nio.file.Paths;
import java.nio.file.StandardOpenOption;

public class FastFileReaderNIO {
    public static void main(String[] args) {
        String filePath = "path/to/your/file.txt";
        try (FileChannel fileChannel = FileChannel.open(Paths.get(filePath), StandardOpenOption.READ)) {
            ByteBuffer buffer = ByteBuffer.allocate(8192); // 8KB buffer
            while (fileChannel.read(buffer) != -1) {
                buffer.flip();
                while (buffer.hasRemaining()) {
                    byte b = buffer.get();
                    // 处理每个字节或字符
                    processByte(b);
                }
                buffer.clear();
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private static void processByte(byte b) {
        // 处理每个字节的逻辑
        System.out.print((char) b);
    }
}