我有两张桌子,t_tran_log和t_item_master。当我对t_tran_log运行这个查询时,我得到了准确的结果: declare @startdate as datetime; declare @enddate as datetimecast(t.start_tran_date+t.start_tran_time - '1900-01-01 05:00' as date) tran_date,sumt.start_tran_tim
我有一个三个表设置:孩子,玩具和游戏,每个都有唯一的主键: id_kid,id_toy和id_game。每个孩子可以有多个玩具和游戏,但每个玩具或游戏只属于一个孩子。,但是结果是加倍的:SUM(CASE toys.bought WHEN 1 THEN,
SUM(CASE games.bought WHEN -1 THEN 1 ELSE 0 END
以excel格式链接到所有数据库表: select c.customerid, customername, sum(d.depositamount) as 'Total Deposit', sum(w.withdrawalamountc left outer join deposits d on c.customerid = d.customerid
left outer join withdrawals w on
(a.val), sum(b.val) from a inner join b on a.id = b.id group by a.id;| id | sum(a.val) | sum(b.val) || a | 2 || c | 6 | 17 |
+------+------------+------------
下面的SQL查询正在生成加倍的netincome sum(ifnull(applicantEmployment.netIncome,0)),FROM
lead LEFT OUTER JOIN applicant ON (lead.leadId=applicant.leadId ANDapplicant.leadApplicantId AND applicant.deleted = 0 AND
列出订单的客户名称、订单状态、订购日期、订单上的项目计数和订单上的平均订购数量(如果订单上的项目数量大于300 )。我想出的答案是.FirstName AS 'Customer Name', ssoh.OrderDate AS 'Date Order',
SUMSales.SalesOrderHeader ssoh ON pp.BusinessEntityID = ssoh.
我有以下两个表,我想找出表1和表2在“一月”月份的差异。差值应该是表1中1月份所有值的总和减去表2中1月份所有值的总和。我的问题是: SELECT (SUM(a.cost2)) - (SUM(b.cost2)) AS difference Table1 a Table2 b ON a.Month = b.Month a.month = 'January' a.month