Kotlin流如何组合两个流并仅在第一个流发送元素时发出结果

import kotlinx.coroutines.delay
import kotlinx.coroutines.flow.Flow
import kotlinx.coroutines.flow.collect
import kotlinx.coroutines.flow.flow
import kotlinx.coroutines.runBlocking

fun main() = runBlocking {
    val flow1 = flow {
        for (i in 1..5) {
            delay(100)
            emit(i)
        }
    }

    val flow2 = flow {
        for (i in 6..10) {
            delay(200)
            emit(i)
        }
    }

    flow1.zip(flow2) { value1, value2 ->
        "Result: $value1, $value2"
    }.collect { println(it) }
}

Result: 1, 6
Result: 2, 7
Result: 3, 8
Result: 4, 9
Result: 5, 10