我尝试按月计算售出的数量,并得到一个数组。 $q = SELECT COUNT(id) AS January FROM tableName WHERE status='sold' AND month = '1'SELECT COUNT(id) AS February FROM tableName WHERE status='sold' AND month = '2'
print_r($row);
因此,我在网上查看了如何找到将MySQL查询计数结果转换为整数的方法,以便将其赋值为php变量,我找到了几个不同的链接,并阅读了多个文档。他们似乎都没有完全涵盖我想要的东西。$result) die($db->error);
现在,在运行查询之后,上面的代码应该返回1,如果username字段是唯一的,并且只有一个查询结果的实例。SELECT COUNT(*) FROM `user_table` WHERE `username` = 'John12' AND `
当我手动检查phpmyadmin时,我的sql查询运行良好,但当我尝试通过php mysql_query处理它时,会抛出一个语法错误。如何解决这个问题?错误消息:You have an error in your SQL syntax; check the manual that corresponds to your MySQL"INSERT INTO scores( user_id ) VALUES (LAST_INSERT_ID( ));";
$result = m
当我从PHP MyAdmin运行SQL查询时,它会正确插入行;当我从PHP运行它时,它不会。现在在PHP MyAdmin中:
SET @type := (SELECT `typeID` FROM `ArbuckleType` WHERE `typeName` = 'A la Carte');# MySQL@item:=(SELECT `itemID` FROM `ArbuckleItem` WHERE (`itemName` = 'Salmon' AND `groupID` = @group));# MySQL
我得到了一个MySQL查询:SELECT , B.POR_MADURACION当我使用PHP的mysql_query()运行这个查询时,我得到以下错误:
You have an error in your SQL syntax; check the manual that correspondsto your MySQL server version for
openingId = 1 ; UPDATE purchase SET qtyUsed = qtyUsed + 25 WHERE purchaseId = 1";
$updateAllStock = mysql_query这会产生错误:Data Not InsertedYou have an error in your SQL syntax; check the manual that corresponds to your MySQL
但最主要的原因是查询被插入到了错误的位置。但我想我把它放对了。所以问题是,即使数据被插入到数据库中,我仍然得到0。有没有人知道我可能错在哪里?下面是我的代码: $this->arr_kolommen = $arr_kolommen; $result = mysql_query($insert,$this->db) or die ($this->sen