我有一个工作的SQL查询。SELECT stuid,grade,SUM(full_amount) FROM due_payments group by stuid having SUM(full_amount) !=15600$someVariable = Input::get(15600);
$results =
Mysql查询如下: GROUP_CONCAT(DISTINCT 'ifnull(SUM(case when location_code = '''location_code , '`' ) INTO @sql item_details;
SET @sql = CONCAT('SELECT item_number,SUM(quantity) as &qu
---------+--------+--------+--------+-----------+---------------------+---------------------+ ->groupBy('employee_id')
->selectRaw('store_incomes.* , sum(gross) as total_gross , sum(income) as tot
我有MySQL查询,我想转换成Laravel雄辩SELECT a.transaction_number a.date, a.item_number, b.desc, a.variant_code, sum(a.quantity) AS quantity, a.costJOIN `items` AS b ON b.id = a.item_numberWHERE a.item_number = 0101010
我的Laravel查询不能正常工作。但是MySQL查询工作正常$data = DB::table(DB::raw('select (sum(case when type="credit" then amount else-amount end)) - (select sum(amount) from total) from report'))
请参考sqlfiidle:中的mysq
我的查询如下:* (SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ks) t1 (SELECTks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks) t2我想把它改成拉拉雄辩。\DB::select(\DB::raw(" FROM
下面我粘贴了mysql查询。请帮助我将此查询转换为laravel 5。selectsum(case when t.status_id = 1 then t.count else 0 end) as status_1,sum(case when t.status_id = 0 and t.status_desca