Node.js:如何在JSON中捕获A值

{
  "name": "Alice",
  "age": 25,
  "address": {
    "city": "Wonderland",
    "zip": "12345"
  },
  "scores": [85, 90, 78]
}

const data = {
  "name": "Alice",
  // ... 其他属性
};

// 假设我们要获取"name"的值
const aValue = data.name; // 或者 data['name'];
console.log(aValue); // 输出: Alice

const jsonString = '{"name": "Alice", "age": 25}';

try {
  const data = JSON.parse(jsonString);
  const aValue = data.name;
  console.log(aValue); // 输出: Alice
} catch (error) {
  console.error('解析JSON时出错:', error);
}

const data = {
  // ... 同上
};

function findValue(obj, keyToFind) {
  for (const key in obj) {
    if (key === keyToFind) {
      return obj[key];
    }
    if (typeof obj[key] === 'object') {
      const result = findValue(obj[key], keyToFind);
      if (result !== undefined) {
        return result;
      }
    }
  }
}

const aValue = findValue(data, 'name');
console.log(aValue); // 输出: Alice

const aValue = data.name || '默认值';