我是R的初学者,我不知道我的标题是否适合这个问题,我在从R中的sql中提取一些数据时遇到了问题,这是代码
> flights = select(paste("SELECT DISTINCT flight FROM messages ORDER BY id DESC LIMIT", 1000))
> flights = select(paste("SELECT DISTINCT flight FROM messages ORDER BY id DESC LIMIT", 10000))
> flights = select(paste("
以下尝试:
Article.objects.filter(category__id="b5e20323-8cec-413a-b405-342b3809f9a4").distinct('title').order_by("?")
给我:
ProgrammingError:选择DISTINCT ON表达式必须与表达式的初始顺序匹配
我试图跳转到原始SQL。所以我试着:
SELECT * FROM (SELECT DISTINCT title from article WHERE category_id = '...') AS in
我对SQL和Server很陌生,很难理解查询中不同子句的处理顺序。
我有一个疑问:
SELECT DISTINCT TOP(10) name
FROM tblEmployees
ORDER BY birthday;
据我了解,查询的实际处理顺序是:
FROM
SELECT
ORDER BY
然而,在我看来,像DISTINCT和TOP这样的子句依赖于ORDER BY子句的结果。因此,如果SELECT子句在ORDER BY子句之前执行,那么DISTINCT和TOP如何使用ORDER子句的结果?
我希望显示两个不同表的值,以及该表中的两个不同列,并按升序排序。
我该怎么做呢?
我使用它来显示两个表的值,但仍然坚持按升序排序:
select
distinct varWinePrice
from
tbl_wines
union
select
distinct varPrice
from
tbl_price
我需要从数据库中获取详细信息。我的代码中有什么地方错了吗?
SELECT DISTINCT FNAME, LNAME, MEMBERORG, DAYCOUNT, TIMESTAMP, COUNT(FNAME) AS total,(SELECT COUNT(*) FROM REPORT_VIEW_PAGE) AS tot
FROM REPORT_VIEW_PAGE
WHERE ID = '68' AND TYPE = 'node'
GROUP BY FNAME, LNAME, MEMBERORG, DAYCOUNT, TIMESTAMP
ORDER BY TIT
这是工作的.
function get_distinct_size_for_bracelets() {
$sql = "SELECT DISTINCT size FROM mytable WHERE id = 27 AND type='plastic' ORDER BY size";
}
,这是不起作用的,并且停止了php的死,没有错误报告.
function get_distinct_size_for_bracelets($myvalue) {
$sql = "SELECT DISTINCT size FROM mytable WHE
我需要一个清单的独特的电子邮件地址跨越两个表。例如,我有以下选择:
select distinct
email
from
contacts
order by
email
select distinct
email
from
customers
order by
email
如果我只需要其中之一,小菜一碟。如果我想把它们并排成两列,那也是小菜一碟。
但是如何将它们作为一列,没有重复,排序呢?这将在Azure Sql数据库上运行,如果有用的话。
我想从数据库中选择唯一的图像。我正在使用以下查询,其中包括一个特定的图像,(ID=11),但是我得到了一些重复的图像:
$photo=mysql_query("SELECT A. * FROM (
SELECT * FROM profile_images
WHERE approved='N'
ORDER BY (ID = 11) DESC, RAND()
LIMIT $sn)
as A ORDER BY RAND()");
我可以把DISTINCT放在哪里?我试过:
$photo=mysql_query("SELECT A. * FRO
嗨,我在查询中出错了。
select
distinct convert(varchar (12),date,105) as Mydate,count(itemcount)
from
Productiontbl
group by
date
order by
cast(run_date as date) desc
错误:-如果指定select DISTINCT,按项排序必须出现在SELECT列表中。
这是我想出的方法,将“default”放在最上面,并对其余的进行排序:
SELECT 'default' AS name, 'AAA' AS tag
UNION
SELECT name, name AS tag
FROM (SELECT DISTINCT TOP (100) PERCENT name
FROM AccountManager
WHERE (name <&g
我有一个数据库,在那里我要查询它以检索计数。我现在的问题是:我正在做一个select语句,如下所示
Select count(distinct(ID)) as countID
,Activity
from Activity_Data
group by Activity_rank
order by countID desc
把这个还给我
Activity Distinct Count
AAA 100
BBB 90
CCC 80
我想要实现的是滚动计数
Activity Distinct Count Rolling Count
AA
我有下面的SQL查询,其中创建的列是无序的,我不太确定如何修复它。
SELECT rhead.rhcust AS [Cust ID], rdetl.rdextp AS [Inv Amt], rhead.rhivdt AS [Inv Date]
INTO #TempTable
FROM rhead
LEFT OUTER JOIN rdetl
ON rhead.rhinvc = rdetl.rdinvc
WHERE rhead.rhivdt >= '01-01-2012' AND rhead.rhivdt <= '12-25-12'
ALTER
我在合并三个select语句时遇到了很大的困难,我尝试了联合它不起作用,因为单独的select语句是有效的,但是我需要其余的语句成为一个快速的语句,如果可能的话,甚至把最后的记录随机排列。
SELECT DISTINCT email
FROM customer_1_tbl
WHERE email NOT IN (SELECT temp.email
FROM temp_emails AS temp)
AND substring_index(email, '@', -1)
我有以下疑问: SELECT
p.ID,
p.DESCRIPTION,
STUFF((SELECT '; ' + col.CUST_ORDER_ID
FROM CUST_ORDER_LINE col
WHERE col.PART_ID = p.ID
ORDER BY col.CUST_ORDER_ID
FOR XML PATH('')), 1, 1, '') [Customer Orders],
STUFF((SELEC
假设有一个配置文件,其中包含字段昵称、全名。昵称字段是文本。我希望按文本字段以不区分大小写的方式对该表进行排序,删除昵称字段的重复项。我怎么发动汽车呢?
有这样的记录
CREATE TABLE profile(
nickname text,
fullname text );
SELECT DISTINCT * FROM profile
ORDER BY lower(nickname)
错误显示为ERROR: for SELECT DISTINCT, ORDER BY expressions must appear in select list
不幸的是,lower ()
我有一段这样的代码:
IF EXISTS(SELECT VALUE
FROM tableA
WHERE nameid = 'thisName')
BEGIN
SELECT distinct VALUE
FROM tableA
WHERE nameid = 'thisName'
ORDER BY value
END
ELSE BEGIN
SELECT distinct VALUE
FROM tableB
WHE
所以我知道如何让前5名和后5名自己显示出来。问题是我如何将两者结合在一起以同时显示。这就是我所拥有的,但它只显示了底部的5个。 SELECT SAL FROM
(
SELECT DISTINCT SAL FROM EMP WHERE SAL IS NOT NULL ORDER BY SAL DESC
)
WHERE ROWNUM <6 AND
SELECT SAL FROM
(
SELECT DISTINCT SAL FROM EMP WHERE SAL IS NOT NULL ORDER BY SAL ASC
)
WHERE ROWNUM <6;
您好,到目前为止,我有以下两个运行良好的指标:
-- --------------------------------------------
-- Nb Unique Accounts
-- -------------------------------------------
select count(distinct(O.user_id))
from DB.order O LEFT JOIN DB.orderCompleted OrC
ON O.id = OrC.order_id
where reason in ('2')
我试图从两个不同的数据集中查询两个bigquery表,以获得两个不同的列。我已经尝试过联合和加入,但他们并没有给我想要我的需要。下面是我尝试过的查询
with abagrowth as (
SELECT
session abas,
term abat,
COUNT(distinct studentid) AS acount,
ROUND(100 * (COUNT(distinct studentid) - LAG(COUNT(distinct studentid), 1) OVER (ORDER BY session)) / LAG(COUNT(distinct student
我有一个表漏洞,我想从这些漏洞中查询按严重程度排序的记录(列)。严重性列包含“高”、“中等”、“低”的值。
下面给出的查询会给我带来错误:
对于SELECT DISTINCT,ORDER表达式必须出现在select列表中“
SELECT DISTINCT vuln
FROM Vulnerabilities vuln
WHERE (lower(vuln.dsc) LIKE '%tomcat%')
ORDER BY CASE vuln.severity
WHEN 'High' THEN 1
WHEN
我想聚合字符串并将它们连接起来。这就是我使用的例子。
SELECT deptno, LISTAGG(ename, ',') WITHIN GROUP (ORDER BY ename) AS employees
FROM emp
GROUP BY deptno;
DEPTNO EMPLOYEES
---------- --------------------------------------------------
10 CLARK, CLARK,KING,MILLER, MILLER
20 ADAMS, ADAMS, ADAMS,
我有一个要求,从雇员表iam使用下面的查询,但得到错误,谁可以帮助前2个薪水?
SELECT iICompanyID,
iIsequence
FROM employee
WHERE dIAmount IN (SELECT MAX(dIAmount)FROM employee)
OR dIAmount IN ((SELECT MAX(diamount)
FROM employee
WHERE diamount IN (SELECT dIAmount
这似乎比它应该做的更难:
我希望能够根据表的copy_count对表进行排序,然后只选择具有唯一标题的事件,并将查询限制在前99个。
Event.order("copy_count DESC").select("DISTINCT ON (events.title) *").limit(99)
这会抛出一个错误:
ActiveRecord::StatementInvalid: PG::Error: ERROR: SELECT DISTINCT ON expressions must match initial ORDER BY expressions
这表明我
我有以下疑问:
SELECT
p.`ID`,
(SELECT COUNT(`ID`) FROM `comments` c WHERE c.`post_id` = p.`ID`) AS `comments`,
(SELECT COUNT(`ID`) FROM `likes` l WHERE l.`post_id` = p.`ID`) AS `likes`
FROM `posts` p
我希望根据第三列对结果进行排序,第三列将按以下方式计算:
order = comments * 6 + likes * 4
如何创建这个“虚拟”列并在计算中使用其他两个列的结果?
谢谢!
我有一个包含城市名称数据的表,比如“(伊斯坦布尔)”和“伊斯坦布尔”。 我试图只显示城市名称,无论它是在原始形式还是在括号中。 为此,我使用以下代码。 <?php
require_once "config.php";
$sql = $conn->query( "SELECT DISTINCT city FROM countries ORDER BY city" );
if ( $sql->num_rows > 0 ) {
// output data of each row
while ( $row = $sql->fetch_a
我有一张表,上面有国家的名字。表中国家/地区名称重复。例如,假设表中有8行,5行带有country Germany,3行带有country UK。我想把表中的国家数一数。我应该得到数字2)。但是我想不出这个查询 我尝试过SELECT Country FROM Customers;,但那会给我8行。我尝试过SELECT DISTINCT Country FROM Customers;,但它给了我两行。我尝试使用count作为SELECT DISTINCT Count(Country) FROM Customers;,但得到了8(可能是因为DISTINCT应用于SELECT Count(Coun
这些都是我的问题,我打算把它们结合起来,并创建一个,但不确定如何。
select SN, COUNT(distinct SB)
from SBS
where SB is not null
group by SN
order by COUNT(Distinct SB) desc
select a.SN, COUNT(distinct a.SB)
from SBS a
inner join SC b
on a.CN = b.CN
group by a.SN
order by COUNT(distinct a.SB) desc
我有一个大约70K的订单表,如下所示:
我想,在每个客户的基础上,确定什么是最常见的订单,以及该订单的确定性(样本大小和概率)。
到目前为止,这就是我所拥有的:
CREATE VIEW CustomerOrderProbabaility as
SELECT Distinct(customerID)
customerID,
order,
COUNT(*) as sampleSize
FROM (Select customerID, order1 AS order FROM orderTable UNION
Select cu
我不是sql专家,但我有一个计算每个经销商的客户数量的查询。
SELECT d_id, COUNT(DISTINCT c_number)
from distinct_customers
group by d_id
limit 5;
但是,它只返回前几个结果。
我正在尝试创建一个从最大到最小限制到5的返回结果的查询。
是否可以创建在sql下面生成的标准:
select name from (select distinct name from person) as aliasname order by lower(name);
这里有两个sql -
select distinct name from person
select name from <output of 1> as aliasname order by lower(name)
我想要创建条件,然后执行criteria.list()