Pandas df按照出现的顺序计算与其他列匹配的值

import pandas as pd

data = {'A': [1, 2, 3, 4, 5],
        'B': [2, 4, 6, 8, 10],
        'C': [3, 6, 9, 12, 15]}

df = pd.DataFrame(data)

df['Matched'] = None

for index, row in df.iterrows():
    matched_value = None
    for column in df.columns:
        if column != 'Matched':
            if row[column] == row['A']:
                matched_value = row[column]
                break
    df.at[index, 'Matched'] = matched_value

print(df)

   A   B   C Matched
0  1   2   3       1
1  2   4   6       2
2  3   6   9       3
3  4   8  12       4
4  5  10  15    None