Python :如果括号序列和其中的内容仅位于字符串的末尾，则将其删除

import re

def remove_brackets(s):
    # 判断字符串中是否存在括号序列
    stack = []
    for c in s:
        if c in "([{":
            stack.append(c)
        elif c in ")]}":
            if not stack or not is_matched(stack[-1], c):
                return "非法的括号序列"
            stack.pop()

    # 判断括号序列是否仅位于字符串的末尾
    if not re.search(r"\([^()]*\)$|\[[^\[\]]*\]$|\{[^{}]*\}$", s):
        return "括号序列不仅位于字符串的末尾"

    # 删除括号序列
    match = re.search(r"\([^()]*\)$|\[[^\[\]]*\]$|\{[^{}]*\}$", s)
    start, end = match.start(), match.end()
    return s[:start] + s[end:]

def is_matched(left, right):
    return (left == "(" and right == ")") or \
           (left == "[" and right == "]") or \
           (left == "{" and right == "}")

# 测试示例
s = "Python (If brackets sequence and its contents are only at the end of the string), remove them."
result = remove_brackets(s)
print(result)

Python, remove them.