Python -使用Popen在子流程中逐行打印时使用超时

import subprocess
import time

def run_command_with_timeout(command, timeout):
    # 创建子进程
    process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, shell=True)

    # 设置开始时间
    start_time = time.time()

    # 循环读取子进程输出
    while True:
        # 检查是否超时
        if time.time() - start_time > timeout:
            # 超时，终止子进程
            process.terminate()
            return None

        # 读取一行输出
        output = process.stdout.readline().decode().strip()

        # 输出为空，子进程已结束
        if not output:
            break

        # 打印输出
        print(output)

    # 等待子进程结束
    process.wait()

    # 返回子进程的返回码
    return process.returncode

# 示例用法
command = "your_command_here"
timeout = 10  # 超时时间为10秒

returncode = run_command_with_timeout(command, timeout)
if returncode is None:
    print("Command timed out")
else:
    print("Command returned with exit code:", returncode)