Python，如何在2D空间中找到下一个最近的可用点？

import math

def find_nearest_available_point(current_point, available_points):
    distances = []
    
    for i, point in enumerate(available_points):
        distance = math.sqrt((point[0] - current_point[0])**2 + (point[1] - current_point[1])**2)
        distances.append((distance, i))
    
    distances.sort()
    nearest_point_index = distances[0][1]
    nearest_point = available_points[nearest_point_index]
    
    return nearest_point

# 示例用法
current_point = (0, 0)
available_points = [(1, 1), (2, 2), (3, 3)]
nearest_point = find_nearest_available_point(current_point, available_points)
print(nearest_point)  # 输出：(1, 1)