Python，解包和重新排序有序字典的列表

ordered_dict_list = [{'name': 'Alice', 'age': 25}, {'name': 'Bob', 'age': 30}, {'name': 'Charlie', 'age': 35}]

for ordered_dict in ordered_dict_list:
    for key, value in ordered_dict.items():
        print(key, value)

name Alice
age 25
name Bob
age 30
name Charlie
age 35

ordered_dict_list = [{'name': 'Alice', 'age': 25}, {'name': 'Bob', 'age': 30}, {'name': 'Charlie', 'age': 35}]

sorted_list = sorted(ordered_dict_list, key=lambda x: x['age'])

for ordered_dict in sorted_list:
    print(ordered_dict)

{'name': 'Alice', 'age': 25}
{'name': 'Bob', 'age': 30}
{'name': 'Charlie', 'age': 35}