假设这棵二叉树是按级别顺序排列的:我想返回一个指向第五个节点的指针。我在构造函数时遇到了困难。= NULL) if(r->count == x) {return r;} {GetNodeAtCount(r->left, x); // my problem is here
GetNodeAtCount(r->
我正在尝试编写一个函数,该函数使用发音字典生成单词的每个可能的发音排列。Unfortunately this does not return the right values[1] "c->k,ou->uh,n->n,t->t,r->r,y->ee,c->k,o->oh,c->k,o->uh,"
[2] "c->s,ou->uh,n->