Scala Circe无法解码包含列表成员的模型

import io.circe._
import io.circe.generic.semiauto._

case class Person(name: String, age: Int, friends: List[String])

object Person {
  implicit val decoder: Decoder[Person] = deriveDecoder[Person]
  implicit val encoder: Encoder[Person] = deriveEncoder[Person]
}

import io.circe.parser._

val jsonStr = """
{
  "name": "Alice",
  "age": 30,
  "friends": ["Bob", "Charlie"]
}
"""

val result = decode[Person](jsonStr)

result match {
  case Right(person) => println(person)
  case Left(error) => println(s"Decoding failed: $error")
}

import io.circe.syntax._

val person = Person("Alice", 30, List("Bob", "Charlie"))

val json = person.asJson

println(json)