SendGrid API v3 post中断示例

import requests
import json

def send_email(api_key, from_email, to_email, subject, content):
    url = "https://api.sendgrid.com/v3/mail/send"
    headers = {
        "Authorization": "Bearer " + api_key,
        "Content-Type": "application/json"
    }
    data = {
        "personalizations": [
            {
                "to": [
                    {
                        "email": to_email
                    }
                ],
                "subject": subject
            }
        ],
        "from": {
            "email": from_email
        },
        "content": [
            {
                "type": "text/plain",
                "value": content
            }
        ]
    }

    try:
        response = requests.post(url, headers=headers, data=json.dumps(data))
        response.raise_for_status()
        print("Email sent successfully!")
    except requests.exceptions.RequestException as e:
        print("Failed to send email:", str(e))

# 使用示例
api_key = "YOUR_SENDGRID_API_KEY"
from_email = "sender@example.com"
to_email = "recipient@example.com"
subject = "Hello"
content = "This is a test email."

send_email(api_key, from_email, to_email, subject, content)