Typescript -一个数组中的校验值出现在另一个数组中

let numbers: number[] = [1, 2, 3];
let strings: string[] = ['a', 'b', 'c'];
let mixed: (number | string)[] = [1, 'a', 2, 'b'];

// 定义校验值数组和待校验数组
let checkValues: number[] = [1, 3, 5];
let valuesToCheck: number[] = [2, 4, 6, 1, 3];

// 检查校验值是否出现在待校验数组中
function checkValuesExist(checkValues: number[], valuesToCheck: number[]): boolean {
    for (let value of checkValues) {
        if (valuesToCheck.includes(value)) {
            return true;
        }
    }
    return false;
}

// 使用示例
if (checkValuesExist(checkValues, valuesToCheck)) {
    console.log("校验值存在于待校验数组中");
} else {
    console.log("校验值不存在于待校验数组中");
}

function checkValuesExistOptimized(checkValues: number[], valuesToCheck: number[]): boolean {
    let valueSet = new Set(valuesToCheck);
    for (let value of checkValues) {
        if (valueSet.has(value)) {
            return true;
        }
    }
    return false;
}

let mixedCheckValues: (number | string)[] = [1, 'a', 3];
let mixedValuesToCheck: (number | string)[] = [2, 'b', 1, 'a'];

function checkValuesExistMixed(checkValues: (number | string)[], valuesToCheck: (number | string)[]): boolean {
    let valueSet = new Set(valuesToCheck);
    for (let value of checkValues) {
        if (valueSet.has(value)) {
            return true;
        }
    }
    return false;
}