My controller,alchemyapi.php and example.php位于同一个目录中。下面是我如何在本机代码中包含alchemyapi.php$alchemyapi = new AlchemyAPI("MY API KEY"); ?require_once 'alchemyapi.php';
$alchemyap
我在我的系统上安装了AlchemyApi,并获得了Api密钥。(AlchemyAPI.java的http.HttpClient.New(HttpClient.java:338):869) at com.alchemyapi.api.AlchemyAPI.GET(AlchemyAPI.java:839) at com.alchemyapi.api.AlchemyAPI.URLGetRankedNamedEntities(AlchemyAPI.java:1
当从API调用中提取这些信息时,我得到的错误如下所示,
'java.io.IOException:错误生成API调用:无法-检索:下游-http-错误:404. at com.alchemyapi.api.AlchemyAPI.GET(AlchemyAPI.java:914) at com.alchemyapi.api.AlchemyAPI.GET(AlchemyAPI.java:914) at com.alchemyapi.api.AlchemyA
我基本上想跳过第一个标签,然后打印第二个标签:
<usage>By accessing AlchemyAPI or usinginformation generated by AlchemyAPI, you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.co
AlchemyAPI的免费用户可以每天拨打1000个请求()。我一直在使用python访问API,如下所示:demo_text = 'Yesterday dumb Bob destroyed myI guess I will have to head over to the Apple Store and buy a new one.'
response = alchemyapi.keywords