SDK includes a Dockerfile that builds the C program in client/example.c and installs the binary as /blackboxThe key line in the sample Dockerfile is:
Insteadexample.c and installing the binary as an action, we’l
System.String agent, System.String version) [0x00001] in <5285048db55d447fae3be4c32e253dbd>:0
at BlackBox.BlackBox..ctor (BlackBox.BlackBox+AppFunction appFunction) [0x00198] in <5285048db55d447fae3be4c32e253dbd>:0at BlackBox.MainClass.Main
我试图编写一个函数,它接受一个字符串,两次调用一个第三方库,如果结果恰好是相同的类型,并且该类型是有序的,则根据该字符串比较这些项。例如(这不是编译,但希望能传达我的意思): val aa = libraryFunction(0) (c, aa, bb) match {
case [A <: Ordered[A]](