假设我有一个结构,例如: double a; int c;将fooA和fooB之和(都是Foo类型)等于: fooA.b + fooB.b, 现在我的问题是,是否可以创建一个泛型函数,以这种方式将结构和在一起?即:StructType sumStructs(StructType A, StructType B) {
// sum component with
R中用于对单词列表进行“求和”的函数,例如: A = list (c ("Flower", "Car"), "Moto")
B = list ("Blue", c ("Black", "Red"))结果是C++ C = list (c ("Flower", "Car", "Blue"), c ("Moto", "Black", "R
CV_TM_SQDIFF:CV_TM_SQDIFF_NORMED:根据文档,从源图像对模板图像和图像修补中的所有像素进行求和。对于具有1 (fully opaque)的像素,我想要做正常的求和。因此,我对特定(x,y)的R求和将变成如下所示: [These pixels have a alpha channel = 0, the other pixels ar