select DISTINCT(cctv_id), cctv.[name] from points_cctv left join cctv on points_cctv.[cctv_id] = cctv.[id]
我想要计算points_cctv where points_cctv.[cctv_id] = cctv.当我插入count(points_cctv.[cctv</
下面是来自某个telnet服务器的响应
String response = "I:BARCO@noiclt22815||K:CMS||O:REgetPerspectiveList||A0:googleP||A1:yahooP||A2:gmail||A3:test||A4:hello||A16:CCTV Barco||A17:CCTV: Corridor CC||A18:CCTV: DR Andy Warhol||A19:CCTV: DR Gaudi (Analog)||A20:CCTV<
我有一些密码:AS FROM cctv1_details AS ALFET JOIN cctv3_details AS B ON (A.CDE_WR = B.CDE_WR) AND A.CDE_dist = B.CDE_distCREATE ORREPLACE TEMPORARY VIEW cctv_join_2 (SELECT *
FROM c
我有三个表:入侵、警报和CCTV,我想使用一个case语句来获取对象的registration_number及其位置,这取决于是闭路电视还是警报触发了入侵表中的入侵事件。这是入侵表:这是警报台:
中央电视台的表和警报表类似,这是我的代码: ALARM_ID, CASE AND CCTV_ID IS NOT NULL (