我正试图在我的Chrome插件中加载一个wasm模块。Chrome抱怨由emscripten生成的wasm模块中有以下功能。它运行在以下js上
Uncaught EvalError: Refused to evaluate a string as JavaScript because 'unsafe-eval' is not an allowed source of script in the following Content Security Policy directive: "script-src 'self' blob: filesystem:
我有一个JavaScript文件,e.js
var global = Function('return this')();
var i = 1;
console.log(eval("100-1"));
console.log(eval("i"));
console.log(global.eval("100-1"));
console.log(global.eval("i"));
当我通过V8执行它时:
$ node e.js
99
1
99
undefined:1
i
^
ReferenceError: i
//Admin.js
var insertAdminFeed = function(s, id, timestamp){
var admin_att_new_key = '12345';
var admin_att_new_key2 = 'abc';
var admin_att_new_key3 = 'zyzyz';
var s = 'admin_att_new_key';
console.log(global[s]); //should print '12345'
};
我在D3中使用eval函数动态创建了scale,但是当我在angular中使用d3时,eval函数不能正常工作,并且在调用scale时出现错误。
TypeError: e.copy is not a function
at SVGGElement.<anonymous> (http://localhost:3000/app/d3.v3.min.js:5:13917)
at http://localhost:3000/app/d3.v3.min.js:3:15103
at Y (http://localhost:3000/app/d3.v3.min.js:1:
我已经在Python中实现了PyV8。我有一个示例javascript文件,如下所示:
main-js.js:
var numOne = 1+2;
var numTwo = 3+1;
var numThree = 5;
如何使用PyV8将每个变量读入Python?到目前为止,我已经打开并读取了这个文件:ctxt.eval(ctxt.eval(“main-js.js”).read())。但我不知道如何从文件中获取每个变量。由于缺乏有关pyv8的文档,因此很难找到它
在JavaScript中使用eval创建JavaScript解释器应该很简单。我得到了这个(使用jQuery终端):
term = $('#term_demo').terminal(function(command, term) {
if (command !== '') {
var result = window.eval("(" + command + ")");
if (result !== undefined) {
term.echo(String(resul
如何引用变量的名称(字面意思是变量的名称)?
我有以下代码:
var thisVariableName = 'path/filename.js';
var script = document.createElement('script');
script.id = **I WANT THE TEXT "thisVariableName" to be added HERE**
script.type = 'text/javascript';
script.src = thisVariableName;
因此,如果输出script.
我有一个JS函数如下所示
// A simple array where we keep track of things that are filed.
filed = [];
function fileIt(thing) {
// Dynamically call the file method of whatever 'thing' was passed in.
thing.file();
// Mark as filed
filed.push(thing);
}
现在,函数fileIt(thing)在调用时运行良好,如下所示
fileIt(AuditF
我正在开发一个游戏,其中我希望有多个脚本,所有实现相同的结构。每个脚本都需要在自己的范围内运行,这样代码就不会与其他脚本重叠。例如:
structure.js
function OnInit() {
// Define resources to load, collision vars, etc.
}
function OnLoop() {
// Every loop
}
function ClickEvent() {
// Someone clicked me
}
// Other fun functions
现在,让我说我有:"BadGuy.js“、
我目前正在用以下java代码执行JavaScript脚本:
ScriptEngine engine = new ScriptEngineManager().getEngineByName("nashorn");
engine.eval(new FileReader("awesome_script.js"));
我需要从JavaScript调用Java函数,所以我在awesome_script.js文件的顶部定义了这个函数:
var first = Java.type('io.github.awesomeprogram.FirstClass');
我有几根绳子
strings = [
"String",
"Object",
"Boolean"
]
我想用它们来声明新的对象
for(var i = 0; i < strings.length; i++){
var x = new strings[i];
}
但是我得到了这个错误:
TypeError: string is not a function
at Object.<anonymous> (/Users/path/code.js)
at Object.<anonymous&