[SubscribeMeterHistory] AS [Extent3] ON [Extent1].[SubscribeMeterHistoryId] = [Extent3].[MeterDefinition] AS [Extent4] ON [Extent3].[MeterDefinitionActiveCode] = [Extent4].[MeterDefinition] AS [Extent5] ON [Extent3].[MeterDefini
我在Entity Framwork中连接两个对象,并将所有条件放在Where子句中。但是我的老板说把所有其他条件都放在Where谓词中会更有效率。像下面这样,第一个是我的版本- join cts in dbContext.ClaimTrackingStatus
on ct.ID equals cts.ClaimTracking
我有一个D3.js图,它在以下情况下工作得很好:(a)有多个数据元素要绘制,(b)如果有正负混合,但如果它违反了这两个规则中的任何一个,我就会遇到问题。我已经创建了一个jsfiddle项目来显示这个问题。在Javascript面板的顶部有三个数据集-如果您注释输入/输出的数组,您可以看到问题:
data = [["A",1],["B",2]];
[Id] AS [Id2], [Extent2].[Name] AS [Name2], [Extent2].[Description] AS [Description2], [Extent2].[LogoType] AS [LogoType], [Extent3].[Id] AS [Id3], [Extent3].[FirstName] AS [FirstName], [Extent3].Extent2] ON [Extent1].[BranchId]
[Requester] AS [Extent6] ON ([Extent2].[Id] = [Extent6].[Requester] AS [Extent10] ON ([Extent8].[Id] = [Extent10].[Requester] AS [Extent12] ON ([Extent8].[Id] = [Extent12].[Requester] AS [Extent13] ON ([Ext