我已经研究了这段代码一段时间了,似乎无法让它正常工作。我试图根据同一列D中单元格的值在列AP中插入一个公式。代码循环通过,但不将公式放在AP列的单元格中。
Sub DTCNFScontract()
Sheets("Cognos Data").Select
Range("A2").Select
Dim LastRow As Long
LastRow = ActiveSheet.UsedRange.Rows.Count
Dim rCell As Range
Dim Rng As Range
Set Rng = Range("D2:D" & L
我的目标是使用Paws sdk创建一个基本的CloudFront发行版,但到目前为止,我还无法使用以下配置通过错误400: use Paws;
use Data::Printer;
my $cloudfront = Paws->service('CloudFront');
my $CreateDistributionResult = $cloudfront->CreateDistribution(
DistributionConfig => {
CallerReference => "1578211502",
Or
我有一个用户模型,如下所示:
var Promise = require("bluebird")
var mongoose = require("mongoose");
var mongooseAlias = require('mongoose-aliasfield');
var bcrypt = Promise.promisifyAll(require('bcrypt-nodejs'));
var Schema = mongoose.Schema;
var userSchema = new Schema({
u:
我有更多关于的问题,但我想问一个新的问题会更好。
完整查询:
SELECT p.id
,(100 * sum((a.price > 0)::int)) / cc.ct AS commercial
,(100 * sum((a.price = 0)::int)) / cf.ct AS free
FROM (SELECT count(*)::float AS ct FROM applications WHERE price > 0) AS cc
,(SELECT count(*)::float AS ct FROM applications WHERE
我想在我的用户模型上写一个"find or create“静态方法--很像upsert,但是pre-save钩子也会在其中运行。
这是我的用户模型:
var Promise = require("bluebird")
var mongoose = require("mongoose");
var bcrypt = Promise.promisifyAll(require('bcrypt-nodejs'));
var Schema = mongoose.Schema;
var userSchema = new Schema({
我有一个与#相结合的元素数组,希望放入散列,该数组的第一个元素作为键,rest作为值,在该数组元素被#拆分之后,但它没有发生。
例如:
my @arr = qw(9093#AT#BP 8111#BR 7456#VD#AP 7786#WS#ER 9431#BP ) #thousand of data
我想要的是
$hash{9093} = [AT,AP];
$hash{8111} = [BR]; and so on
如何利用地图功能来实现它。否则,我需要使用for循环,但我希望使用map函数。
使用默认值的PostgreSQL,加上
default_statistics_target=1000
random_page_cost=1.5
版本
PostgreSQL 10.4 on x86_64-pc-linux-musl, compiled by gcc (Alpine 6.4.0) 6.4.0, 64-bit
我已经吸尘分析过了。查询非常简单:
SELECT r.price
FROM account_payer ap
JOIN account_contract ac ON ap.id = ac.account_payer_id
JOIN account_schedule
我创建了一个托管Bean,它从视图读取一系列文档,并为每个文档创建一个HashMap条目。每个Hash条目包含从文档中检索到的一系列值,这些值很少更改,并且在许多地方使用。在任何情况下,HashMap的构建都可以工作,并存储正确的值。如果我按以下方式创建构造函数:
private final Map<String, AppProperties> internalMap = new HashMap<String, AppProperties>();
public ApplicationMap() {
System.out.println("
当我使用这个查询时,总是会显示错误,为什么?在审计类中使用MappedSuperclass。
@Query("select new com.brite.domain.CurrencyConversion(ins.id,ins.contractType,ins.symbol,ins.exchange,ins.currency,ap.allocationQty,ap.createdDate,ca.baseCurrency,hd.close) from ActualPortfolio as ap JOIN Instrument as ins on ins.id=ap.instrument
这是我讲稿中的一个例子。
ap_List :: [a -> b] -> [a] -> [b]
-- ap_List [] as = []
-- ap_List (f:fs) as = map f as ++ ap_List fs as
ap_List fs as = map2_List (\f -> \a -> f a) fs as
-- E.g., ap_List [f,g] [1,2,3] = [f 1, f 2, f 3, g 1, g 2, g 3]
-- = map f [1,2,3] ++ (m
为什么下面的代码不起作用?
#include <stdarg.h>
#include <stdio.h>
// People are missing this in their reponses.... 'fmt' here is passed by
// reference, not by value. So &fmt in _myprintf is the same as &fmt in
// myprintf2. So va_start should use the address of the fmt char * on th
我正在使用node、express和swig。我希望能够基于currentUser进行循环,这对我来说是一个局部变量。我让循环工作,但它为每个用户吐出我们的结果。
下面是我的循环:
{% for ap in aps %}
<tr>
<td>{{ap.name}}</td>
<td>{{ap.manufacturer}}</td>
<td>{{ap.model}}</td>
<td>{{ap.type}}</td>
<td>{{
根据提供的建议,我创建了以下代码:
newtype Ap f a = Ap { getAp :: f a }
deriving (Eq, Show)
instance (Applicative f, Semigroup a) =>
Semigroup (Ap f a) where
Ap xs <> Ap ys =
Ap $ liftA2 (<>) xs ys
instance (Applicative f, Monoid a) =>
Monoid (Ap f a) where
mempty = Ap $ pure