由于Amazon Redhshift SQL (基于PostgreSQL 8.0.2)的局限性。出于其他一些复杂的查询目的,我不得不执行以下查询: create temporary table NS AS (
select 1 as n union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 8 union all
select 9 union all
select 10 union al
insert into rfdate (date)
select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4
union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union selec
我想使用这个查询创建日历表(它在普通SQL中工作)
SELECT DATEADD(day,t4 * 10000 + t3 * 1000 + t2 * 100 + t1 * 10 + t0,'1970-01-01') AS date_value
FROM
(SELECT 0 t0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SEL
如何对此查询执行正确的联接。我有另一个表,我需要根据日期将查询结果右连接到该表。
(SELECT t.date FROM (SELECT ("2018-01-31" - INTERVAL c.number DAY) AS date
FROM (SELECT singles + tens + hundreds number FROM
(SELECT 0 singles
UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3
UNION ALL SELECT 4 UNION ALL SELECT 5 U
我使用的是一个数字匹配表,从上到上。然而,我意识到我需要从零开始。弄不清楚..
CREATE TABLE IF NOT EXISTS util_nums (n integer primary key
autoincrement not null);
insert into util_nums(n) select null from (select 0 as n union select 1
union select 2 union select 3 union select 4 union select 5 union select 6
union select 7 union
以下查询返回开始日期和结束日期之间的所有星期二。在这种情况下,我还需要每隔一个星期二返回一次。
select * from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) DATES from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select
目标是返回一组与请求的星期几对应的日期。
例如:2018-08-13和2018-12-31之间每隔一个星期一。
下面的语句返回所有日期,效果很好
select * from
(select adddate('2010-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) DATES from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 uni
是否有更好的方法生成0. 9999,而不是这样:
SELECT
(a3.id + a2.id + a1.id + a0.id) id
FROM
(
SELECT 0 id UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7 UNION ALL
SELECT 8 UNION ALL
SELEC
目前,我正在使用它,但它有点慢,我最终只有1331条记录。我在想,一定有更快的方法来产生更多的记录?
CREATE TABLE IF NOT EXISTS util_nums (n integer primary key
autoincrement not null);
insert into util_nums values (0);
insert into util_nums(n) select null from (select 0 as n union select 1
union select 2 union select 3 union select 4 union s
我收到了这个错误
1096没有表使用SELECT *
下面是我的代码,不知道哪里出了问题。
public function getH20StockDevelopmentGraph($recStart,$recEnd){
$sql = "SELECT v.DATE,
(SELECT SUM(b.QTY)
FROM tbl_ax_transaction b
WHERE DATE(b.DATEPHYSICAL) <= v.DATE
我需要在sql中生成两个日期之间的日期,如下所示:
我正在使用这个查询:
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union
我需要连接下面select子字符串的2个结果。有什么想法吗?
BEGIN
select SUBSTRING_INDEX(SUBSTRING_INDEX(oldVal, '-', n.n), '-', -1) AS oldVal5
FROM audits oldVal
CROSS JOIN ( SELECT a.N + b.N * 10 + 1 n
FROM (SELECT 0 AS N
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNI
我需要周列表,周号,周开始日期和两个日期之间的结束日期。让我举个例子,
如果我将开始日期作为2019-12-11传递,将结束日期作为2019-12-25传递,那么预期的输出应该如下所示:
Week Number | Week start date | Week end date
W1 2019-12-11 2019-12-14
W2 2019-12-15 2019-12-21
W3 2019-12-22 2019-12-25
我试过使用下面的查询,但是输出如下
Week st
我已经搜索过,但没有找到一个解决方案,如何列出两个日期之间的几个星期。
我找到了解决方案,列出了每月两个日期之间的所有日子:
select * from
(select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select
我试着和工会打折几天一月。但是我在下面的代码中有错误: (SELECT 1 AS id, a+b AS 'days', 2 AS id2, c+e AS 'months' FROM
((SELECT 0 a UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) a, (SELECT 0 b UNION SELECT 10 UNION SELECT
我有大约1800行数据,格式大致如下: id name id name dob (id name relation dob) x4 并且我必须将上面的内容更改为: id name
id name dob
id name relation dob
x4 我用来手动切换格式的宏用了一分钟多的时间来处理每一行。否则我的成绩就会挂了。 宏是: Sub autof()
'
' autof Macro
'
' Keyboard Shortcut: Ctrl+d
'
'
'
'
'
'
我需要与日期表交叉连接,所以我使用了:
CREATE TEMPORARY TABLE IF NOT EXISTS myDates AS (
SELECT
CAST((SYSDATE()+INTERVAL (H+T+U) DAY) AS date) d
FROM ( SELECT 0 H
UNION ALL SELECT 100 UNION ALL SELECT 200 UNION ALL SELECT 300
) H CROSS JOIN ( SELECT 0 T
UNION ALL SELECT 10 UNION ALL SELECT 20 UNION ALL
我需要将这个查询从MySQL格式转换为SQLite格式。我在努力,但我发现了一些困难。
在SQLite中,curdate()和interval函数不存在。
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 unio
是否可以在mysql中使用茅斯表显示日期范围?我有这个代码,但它没有。
SET @startDate = '2018-10-01';
SET @endDate = '2019-02-21';
select @startDate + INTERVAL seq.seq DAY AS sequential_day
from (
SELECT A.N + 5*(B.N + 5*(C.N + 5*(D.N + 5*(E.N + 5*(F.N))))) AS seq
FROM (SELECT 0 AS N UNION SELECT 1 UNION
我想知道是否可以在不创建任何表和索引的情况下优化这个函数。
这是一项功能:
CREATE OR REPLACE FUNCTION decode_trame_v3(IN tid integer)
RETURNS TABLE(id integer, card numeric, kilo double precision) AS
$BODY$
DECLARE
v_weights character varying;
v_waste_no integer = 0;
v_number_waste integer;
BEGIN
SELECT weights FROM data
我从中知道,我可以很容易地在MySQL中选择一个日期列表。
select * from
(select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9
在尝试执行某种复杂的查询时,我正在使用BigQuery并得到以下错误:
Resources exceeded during query execution: Not enough resources for query planning - too many subqueries or query is too complex.
我使用一个WITH子句来创建一个视图表。这个表由后端Java填充,有很多行(大约900行)。下面是我的存储库类的完整查询:
with weights as (
select 3 as weight, 3000973 as providerId
union all se
我有这样的查询来获取范围日期中的计数值(使用唯一的日期筛选器某一天查看选择细节):
SELECT `dates`.`date`, COUNT(*)
FROM (
SELECT CURDATE() - INTERVAL (units.mul + (10 * tens.mul) + (100 * hundreds.mul) + (200 * thousands.mul)) DAY AS `date`
FROM (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION A
需要有关SQL语句的帮助,该语句将根据以下条件返回日期列表:
每月的第n天。
我有以下语句,它基于循环模式返回日期列表,该模式具有开始和结束日期、重复(例如每x周)和星期几。
CREATE DEFINER=`root`@`%` PROCEDURE `GETEVERYOTHERDATE`(IN _START DATE, IN _END DATE, IN _REC INT(5), IN _DAY VARCHAR(10))
BEGIN
SET CHARACTER SET 'UTF8';
select * from
(select adddate('1970-01-01&
我需要生成2015-1-1和2015-12-12之间的数据,我最近的代码在这里。
set @startdate = '2015-1-10';
set @enddate = '2015-12-12';
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) - (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all sel
我需要总结一些数字,比如
CREATE TABLE #t(num int);
INSERT #t
SELECT 10001 UNION ALL
SELECT 10002 UNION ALL
SELECT 10003 UNION ALL
SELECT 10004 UNION ALL
SELECT 10005 UNION ALL
SELECT 10006 UNION ALL
SELECT 10007 UNION ALL
SELECT 10008 UNION ALL
SELECT 10009 UNION ALL
SELECT 10010 UNION ALL
SELECT 10020 UNION A
我对vba完全陌生。我希望用下面的代码将单元格中的某些值从两个选项卡("Equities“、"Bonds")复制到第三个选项卡("ZSM")中。
Sub AllesAufEinmal()
Call Spalten
Call Wertpapiere
Call Daten
End Sub
Sub Spalten()
'
' Spalten Macro
'
Sheets("Equities").Select
Range("A4").Select
Ran