我需要在3个数组上找到一个解决方案,解析a+b+c= 15 (或其他什么)A = 1:10C = 1:10
solutions = Iterators.filter((a, b, c) -> a + b + c == 15, possibilities)
sol = collect(solutions{UnitRange{Int64},Base.Iterators.Prod2{UnitRan
展平Java中迭代器的迭代器。如果输入为[ 1,2,[3,4,5],6],则应返回1,2,3,4,5,6。实现hasNext()和next()。当内部迭代器或列表为空时要小心。我不认为我的代码适用于多个级别的内部列表。 int index = 0; // keep an index to indicate where the current accessed element is
List<Integer> flattenedList = new ArrayList<>(); // flatt