jQuery- file -upload:如何针对每个文件大小分别发送请求

<script src="https://code.jquery.com/jquery-3.6.0.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery-file-upload/10.0.0/jquery.fileupload.min.js"></script>

<form id="file-upload-form" action="upload.php" method="POST" enctype="multipart/form-data">
  <input type="file" name="file" multiple>
  <button type="submit">上传</button>
</form>

$(function() {
  $('#file-upload-form').fileupload({
    dataType: 'json',
    add: function(e, data) {
      // 针对每个文件大小分别发送请求
      var fileSize = data.files[0].size;
      if (fileSize <= 1024) {
        // 发送小文件的请求
        data.url = 'upload_small.php';
      } else if (fileSize <= 1024 * 1024) {
        // 发送中等文件的请求
        data.url = 'upload_medium.php';
      } else {
        // 发送大文件的请求
        data.url = 'upload_large.php';
      }
      data.submit();
    },
    done: function(e, data) {
      // 文件上传完成后的回调函数
      console.log(data.result);
    }
  });
});