function addTotal(){
var txtTotal = document.getElementById('txtTotal').value;
var txtGrandTotal = document.getElementById('txtGrandTotal');
txtGrandTotal.value += parseInt(txtTotal);
}
this is delete code
$(".delete-row").click(function(){
$("table tbody").fi
我一直收到“您只能输入一个名称”的消息。在我用以下代码创建的peoplepicker输入框(Div)中:
// Render and initialize the client-side People Picker.
function initializePeoplePicker(peoplePickerElementId) {
// Create a schema to store picker properties, and set the properties.
var schema = {};
schema['PrincipalAccountType&
我正在尝试使用java创建一个具有多个选项的弹出输入框,但我不知道最简单的方法是什么。目前,当我在GUI中单击一个按钮时,它会这样做:
public class LoadListAction implements ActionListener{
public void actionPerformed(ActionEvent e){
Object result = JOptionPane.showInputDialog(f, "Test:");
}
}
然而,这只给我提供了确定和取消的选项。我想有一个框,弹出并有选项1和选项2上,并做不
我有一个页面上的输入框,这是通过ajax调用重新加载(内容刷新)。问题是,当输入框中有一个单引号时,剩余值被截断了,我如何解决这个问题?
myVal = <-- its coming dynamically from db and when it contains values like "It's me", next time page reloads It just show "It" in input box
$('#myInput').val(myVal);
//after setting value and doing s