我想根据表“查询”(l_query query%ROWTYPE)创建一个变量,但是我得到了这样的消息:invalid type name "query%ROWTYPE"我也尝试使用完全限定的表名l_query dbname.public.query%ROWTYPE,但是它对我没有帮助。RETURNS int AS $$ l_res dbname.public.query%ROWTYPE; return 1;$$ LANGUAGE plpgsql;
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Myapp is not defined
at C:\Documents and Settings\ssit\My Documents\GitHub\ssit\server\routes\index.jscallbacks (C:\Documents and Settings\ssit\My Documents\GitHub\ssit\node_modules\express\lib\router\index.jsparam (C:\Documents and Settings\ssit\My Documents\GitHub\ssit\node_mod
same as minimal but with TypeScript configuration 作为一个额外的测试,我创建了一个黑色项目,也使用了expo (空白-> --一个与空白画布一样干净的最小应用程序),该应用程序如预期的那样工作.然后我添加了底部选项卡导航所需的npms:
加@react-navigation/nativeyarn加@react-navigation/bottom-tabsyarn加react-native-screensyarn加rea