js怎么解析list集合

let list = [1, 2, 3, 4, 5];
list.forEach(function(item) {
    console.log(item);
});

let list = [1, 2, 3, 4, 5];
let newList = list.map(function(item) {
    return item * 2;
});
console.log(newList); // 输出: [2, 4, 6, 8, 10]

let list = [1, 2, 3, 4, 5];
let filteredList = list.filter(function(item) {
    return item > 2;
});
console.log(filteredList); // 输出: [3, 4, 5]

let list = [1, 2, 3, 4, 5];
let sum = list.reduce(function(accumulator, currentValue) {
    return accumulator + currentValue;
}, 0);
console.log(sum); // 输出: 15

if (list.length > 0) {
    // 执行数组操作
}

let obj = {
    value: 10,
    processList: function(list) {
        list.forEach((item) => {
            console.log(this.value + item);
        });
    }
};
obj.processList([1, 2, 3]);