我的mysql查询如下:
SELECT
`pickupreq`.*,
`pinP`.`Pincode` as PinP,
`pinD`.`Pincode` as PinD,
`tslots`.`StartTime`,
`tslots`.`EndTime`,
`usr`.`FirstName`,
`usr`.`LastName`,
`staff`.`FirstName` as sFirstName,
`staff`.`LastName` as sLastName,
`ord`.`Id` as Or
我需要选择n个表中的所有行,其中n> 15在ms中访问数据集。单个查询导致错误,“定义的字段太多”。我猜它超过了255个字段的极限。
SELECT * FROM ((((((((((((((((Forms
LEFT JOIN Layouts ON Layouts.Name = Forms.Name)
LEFT JOIN Layout ON Layout.Name = Forms.Name)
LEFT JOIN Form ON Form.Name = Forms.Name)
LEFT JOIN Sections ON Sections.ID] = Form.ID)
LEFT JO
假设表TableA、TableB、TableC和TableD
是以下查询:
TableA INNER JOIN TableB LEFT JOIN TableC LEFT JOIN TableD
(全部连接到id列),相当于:
TableA INNER JOIN TableB
INNER JOIN TableC
LEFT JOIN TableD
UNION
TableA INNER JOIN TableB
LEFT JOIN TableC ON TableB.c_id IS NULL
LEFT JOIN TableD
注:
或者,而不
可以像下面这样做case语句和左外部连接吗?我对我想要实现的目标做了评论。
SELECT
eventGame.Id,
eventGame.[Type] AS GameType
FROM GrassrootsHoops.EventGame eventGame
LEFT OUTER JOIN (SELECT
divisionGameTeamResult.Id,
divisionGameTeamResult.GameId,
COALESCE(divisionPool.Name, divisionTeamPoolPoolBracket.Name) AS Divi
我有这个SQL查询
select pr.*,p.id, cf.nome, p.valor_total as "valor total", f.descricao as "forma de pagamento", t.descricao as "tipo de pagamento", s.descricao as "Status" from pedido p
left join cliente c on c.id = p.id_cliente
left join cliente_pessoa_fisica cf on
我已经更改了表名,但我在一个正在优化的SP中发现了这个FROM语句,我想知道这是如何实现的,为什么你会做这样的事情,为什么它仍然有效。
FROM tblPezFill pf
RIGHT OUTER JOIN tblWolveLocation stfl
RIGHT OUTER JOIN tblDuckPez pp
RIGHT OUTER JOIN tblChaos o
INNER JOIN tblBillLeg bi
INNER JOIN @Facty selFac
ON bi.WolveId = selFac.WolveId
ON o.ChaosID = bi.
SELECT * FROM user_info LEFT JOiN general_information ON user_info.username = general_information.vendor_id LEFT JOIN company_information ON user_info.username = company_information.vendor_id LEFT JOIN usa_on_shore_site_locations ON user_info.username = usa_on_shore_site_locations.vendor_id LEFT JOI
我想将以下两个查询合并为一个查询。
我有一项关于居住的询盘已经订好了。
SELECT some coluns
FROM residence r
JOIN project p ON p.ProjectId = r.ProjectId
LEFT OUTER JOIN residencetype rt ON r.ResidenceTypeId = rt.ResidenceTypeId
LEFT OUTER JOIN entity_milestone em ON (r.`Status`='BOOKED' AND em.ResidenceId = r.`
我需要我的所有记录从T3表在下面的查询。如何在oracle中使用left join语句来解决问题。
SELECT COUNT(*)
FROM R
LEFT JOIN RD
ON (R.ID = RD.RES_INFO_ID)
LEFT JOIN RES
ON (R.SEL_EVL_RES_ID = RES.ID)
LEFT JOIN S
ON (S.ID = R.SEL_EVL_ID)
LEFT JOIN D
ON (RD.DEC_DET_ID = D.ID)
LEFT JOIN M
ON (S.EVL_MAS_I
我有一个hibernate查询,我需要简化它,因为它有很多joins。在某些情况下,我觉得连接是不必要的。我试图理解并简化查询,以便在执行后获得相同的结果。但是,我不能这样做。下面是查询:
Select a from Animal a
left join Cat on cat.id = animal.id
left join Dog as dog on cat.id = dog.id
left join Wolf on animal.id = wolf.id
left join Monkey on animal.id = monkey.id
left join Location
我是否可以请求您的协助,以帮助我将此{oj } SQL语法转换为正常的联接语法?
SELECT
...
FROM
{oj (((((((((("VMPH" "VMPH" LEFT OUTER JOIN "VMPT" "VMPT" ON "VMPH"."NMPSTID"="VMPT"."NMPSTID")
LEFT OUTER JOIN "ARRTA" "ARRTA" ON "VMPH"."TXTERM"
SELECT * FROM property
LEFT JOIN installmentagreement
ON property.PId=installmentagreement.PId
LEFT JOIN installments
ON installmentagreement.Id=installments.Id
LEFT JOIN rentagreement
ON property.PId=rentagreement.PId
WHERE property.PId=39
这是按预期工作的SELECT查询。我想删除此SELECT查询的结果。我使用了这个查询。
DELETE FROM pro
我问了,所以我会再试一次(对不起)。您不必详细阅读查询,只是为了给您一个概念。
总之:有问题的查询是这样的,它是由Doctrine2 (I cut SELECT part)生成的
FROM
tbl_story t0_
LEFT JOIN tbl_user t1_ ON t0_.creator_id = t1_.id
LEFT JOIN tbl_image t2_ ON t1_.avatar_id = t2_.id
LEFT JOIN tbl_image t3_ ON t0_.id = t3_.story_id
LEFT JOI
我有这样的疑问:
SELECT 1 as Tipo, 'Total Efectivo'
AS tipo_pago,
ISNULL(SUM(p.monto), 0) AS Total,
suc.su_nombre AS Sucursal
FROM Comprobante c
RIGHT JOIN Pago p ON c.co_idcomp = p.co_idcomp
LEFT JOIN PagoCheque pc ON p.id_pago = pc.id_pago
LEFT JOIN Cheque ch ON pc.
我正在使用下面的代码,但是我没有得到任何结果,请任何人给我一个建议。
users_register表有所有用户的手机号,我有像property,hostels,hotels等12个表。
如何获取不匹配的手机号码
SELECT t1.user_mobileno,
t1.user_fullname
FROM users_register t1
LEFT JOIN userpostproperties t2 ON t1.user_mobileno = t2.property_contact_number
LEFT JOIN services t3 ON t1.user_mobileno
我有这样的疑问:
SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.*
FROM classified mt
LEFT JOIN fordon ON fordon.classified_id = mt.classified_id
LEFT JOIN boende ON boende.classified_id = mt.classified_id
LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_
我有一个MySQL查询,需要两次left join。有四个表A、B、C、D和两种可能性,如果A.label为null,
select ... from A
left join B on B.name=A.name
left join D on B.bid=D.id;
否则,如果A.label不为null,则
select ... from A
left join C on C.name=A.name
left join D on C.cid=D.id;
如果我想通过CASE条件将这两个查询合并为一个查询,我应该怎么做?
我有表电影,movie_client,language_movie,语言,subtitle_movie和字幕
我想选择所有带有字幕和语言的电影,其中client_id (在movie_client中)是1
SELECT * FROM movie
LEFT OUTER JOIN movie_client
ON movie.movie_id = movie_client.movie_client_id
LEFT OUTER JOIN client
ON movie_client.client_movie_id =
我在研究一个权利验证系统。为了验证用户是否有访问文档的权限,我向数据库发出请求,有2种情况下您可以访问:
用户位于此文档的访问区域(例如,在发布文档的聊天中的用户)
select count(*) > 0 from Document
left join Chat
left join ChatUser
left join User
left join Resource
...
where ...
文档是公共的
select count(*) > 0 from Document
left join User
left join Resour
我使用的系统不允许我直接访问SQL数据库,我必须使用它们内置的报告工具,这太糟糕了。我正在运行下面的代码,它告诉我附近有一个语法错误),但是我不知道这是怎么不正确的,有什么想法吗?
SELECT ST.Staff_ID,
COUNT (CASE WHEN Referral_Date BETWEEN @StartDate AND @EndDate ) AS 'Referrals',
COUNT (CASE WHEN Att_Start_Dttm BETWEEN @StartDate AND @EndDate ) AS 'Appointments'
FROM tb
我有一个网站,你可以在那里看到场地。当您单击一个单一的地点,它会显示一个弹出与它。有一个喜欢的按钮,可以是活动的,也可以是不活动的。这个弹出窗口的代码在ajax中。
SELECT * FROM venue_datetime
LEFT JOIN venue_calendar ON venue_datetime.calendar = venue_calendar.calendar_id
LEFT JOIN venue_events ON venue_calendar.event = venue_events.event_id
LEFT JOIN venue ON venue_events.venu
我理解如何与组一起使用count,但我需要具体使用这个反向,我尝试执行以下查询:
SELECT
COUNT(pac.strid_paciente)
FROM tb_paciente AS pac
LEFT JOIN tb_entidades AS ent
ON pac.strid_entidad = ent.strid_entidad
LEFT JOIN tb_escolaridad AS esc
ON pac.strid_escolaridad = esc.strID_Escolaridad
LEFT JOIN
我在多个不同的表中有相同名称的列。我使用JavaScript发送一个包含字段的对象,Node.js包创建一个具有名称的数组,因此,如果两个列的名称相同,则最后一个列的值似乎会放在数组中。
我有个疑问
SELECT *
FROM FACTURATION AS F
LEFT JOIN ENREGISTREMENT AS E ON F.Enregistrement=E.Numero
LEFT JOIN RESTITUTION AS R ON F.Restitution=R.Numero
LEFT JOIN RESERVATION AS X ON F.Numero=X.Facturation
不考虑性能,我会从下面的查询A和B得到相同的结果吗?C和D怎么样?
-- A
select *
from a left join b
on <blahblah>
left join c
on <blahblan>
-- B
select *
from a left join c
on <blahblah>
left join b
on <blahblan>
-- C
select *
from a join b
我还没有弄清楚,如何将这个查询转换成zend框架语法,任何帮助都会被接受。
SELECT p.idProyecto,p.nombre, p.nombre, e.nombre, e.apellido, sum(Respuesta.estimado) as estimado, DATE_FORMAT(p.fechaInicio, '%Y/%m/%d') as inicio, DATE_FORMAT(p.fechaFin, '%Y/%m/%d') as fin, sum(DetailTotals.Total) as total
FROM Actividad as a
我在努力创造
select c.FullName, b.*, e.Description as Posisilama, f.Description as Posisibaru, g.Description,
GROUP_CONCAT('b.nilai' SEPARATOR ',') AS nilai
from penilaian_header a
left join penilaian_detail b on a.KodePenilaian = b.KodePenilaianH
left join employee c on a.N
我有以下查询
SELECT *
FROM tbl_events AS event
LEFT JOIN tbl_business_events AS bevent
ON event.event_id = bevent.event_id
LEFT JOIN tbl_business_sector AS bsec
ON event.event_id = bsec.event_id
LEFT JOIN tbl_sectors AS sector
我有一个查询,它包含一个后跟join的left join。我想确保先完成left join。在我的查询中,left join出现在join n之前,这足够了吗?这就是连接的样子
select * from
(select *....) A
left join
(select *...) B
on A.a = B.a
left join
C
on A.f = C.f
我正在尝试对其他人的MS Access查询进行故障排除,并不断得到一个无效的操作错误。这个帮助似乎不适用,因为我只是在运行一个查询。所有这些都以INNER JOINS的形式工作,但当我切换回LEFT JOIN时,会出现错误。
SELECT *
FROM ((((orders
INNER JOIN orders_customers ON orders.CUST_ORDER_ID = orders_customers.ID)
LEFT JOIN quoted_theory ON orders.PART_ID = quoted_theory.PART_ID)
LEFT JOIN co
查看DN7语句。我想我在连接区遗漏了一些东西。
当ca.code = 128或ca.code为106 carrier.name时,需要案例来显示公司表中的company.name。
else ph.name
选择
--TRANSACATION INFO FOR HT
'148' as 'DN1', --TRANSACTION SET ID
isnull(convert(char(2), d9.code), space(2)) as 'D2', --MAINTENANCE TYPE CODE
isnull(left(convert(char(8),