I have files as given below
PALK.BHZ.2012.04.11.11.52.30.390.00.sac..dsp
PALK.BHZ.2012.04.11.11.52.30.390.10.sac.
PALK.BHZ.2012.04.11.11.52.30.390.10.sac..dsp
PALK.BHZ.2012.04.11.11.53.37.380.00.sac.
显示“詹姆斯·D·克莱默”的公司名称。
显示“模块循环系统”的所有地址
显示“CustomerID 635”订单的数量、名称和价目表。
代码片段:
--use [AdventureWorks2016CTP3]
--CAN'T get the required company with this name.
select
[BusinessEntityID], [FirstName], [MiddleName], [LastName]
from
[Person].[Person]
where
[FirstName] = 'J
我会在这里张贴我的剧本
#!/bin/tcsh
echo 'Running'
set fileN = '2021-02-07-0448-04S.JKH_RR.SAC'
set fileE = '2021-02-07-0448-04S.JKH_RR_BHE.SAC'
set compR=BHR
set compT=BHT
set compR_name=BHR.SAC
set compT_name=BHT.SAC
set fileN_rot = `echo $fileN | awk '{split($0,a,".SAC")
我有一个XSA系统和XSA数据库用户。这个XSA用户将用于在XSA中创建新的Hana数据库用户。我正试图在execBatch()功能的帮助下创建一批用户。我对node.js项目有兴趣。
我正在node.js文件中执行sql查询。下面是密码-
console.log("Targeting User Creation")
try{
let createuserstatement = await xsaDbConn.preparePromisified("CREATE USER ? PASSWORD AbcYes NO FORCE_FIRST_PASSWORD_
WITH outer_tbl
AS (
SELECT ROW_NUMBER() OVER (ORDER BY inner_tbl.ctrc_data DESC ) AS KOHANA_DB_ROWNUM, *
FROM (
SELECT * FROM rkm_sac_ctrc
INNER JOIN rkm_sac_nf ON (rkm_sac_ctrc.id_ctrc = rkm_sac_nf.id_ctrc)
WHERE rkm_sac_ctrc.pag_cnpj = '46.344.354/0005-88'
AND rkm
我想做这样的事..。
SELECT lc.Location, count(h.empID) as 'Count', lu.LBL
FROM swam.lookup lu
LEFT JOIN swam.empTable h
ON CASE
WHEN lu.sac is null
THEN lu.POS = h.POS
ELSE (
lu.POS = h.POS
and
lu.sac = h.sac)
INNER JOIN swa
我有两张桌子
AutoScriptArgumentClass
id
ScriptArgumentClass
AutoTestScriptMeta
id
AutoTestScript_id
ScriptArgumentClass_id
这是我的问题。
select sac.id,sac.ScriptArgumentClassType
from AutoScriptArgumentClass sac,AutoTestScriptMeta tsm
where tsm.ScriptArgumentClass_id = sac.id
and tsm.AutoTestScript_id=129
我怎么用y