linux strcpy s

char *strcpy(char *dest, const char *src);

char *strncpy(char *dest, const char *src, size_t n);

#include <stdio.h>
#include <string.h>

int main() {
    char src[] = "Hello, World!";
    char dest[10];

    strncpy(dest, src, sizeof(dest) - 1);
    dest[sizeof(dest) - 1] = '\0'; // 确保字符串以空字符结尾

    printf("Copied string: %s\n", dest);
    return 0;
}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main() {
    const char *src = "Hello, World!";
    size_t len = strlen(src) + 1; // 包括终止符 '\0'
    char *dest = (char *)malloc(len);

    if (dest != NULL) {
        strcpy(dest, src);
        printf("Copied string: %s\n", dest);
        free(dest); // 记得释放内存
    } else {
        printf("Memory allocation failed.\n");
    }

    return 0;
}