存在用于等待任何进程退出的bash脚本用法“wait -n”。但它得到了错误信息。脚本的部分是:# `jobs` ensures that any completed old processesfrom other testsjobs &> /dev/null错误信息
wait: -n: invalid opti
我正在尝试找出在这种上下文中使用Wait和WaitAsync的SemaphoreSlim用法之间的区别:public async Task<string> Get() // What's the difference between using Wait and WaitAsync herethis.semaphore.Wait(); //
wait_queue_t wait; wait_event
/home/user/Downloads/0001-LinuxPkg_5.18rc8/Rt-Linux-HDaudio/include/linux/wait.h:79:20: note: expected ‘struct wait_queue_entry *’ but argument is of
/test/my_test.cpp:98: error: no matching function for call to 'wait::wait(int*)'
/data/backfire/staging_dir/toolchain-i386_gcc-4.1.2_uClibc-0.9.30.1/lib/gcc/i486-openwrt-linux-uclibc/4.1.2/../../..&