FQL代码确实结婚了朋友SELECT uid,name,relationship_status FROM user WHERE (uid = MY_ID或uid IN (SELECT uid2 FROMFROM code uid1 = MY_ID)) AND relationship_status=‘结婚’我认为Graph API也更干净。
我有一个MySQL查询,我认为它会抛出一个异常,但它确实not.Just想找出为什么?查询为:from nov_visit_20161201 and uid in (select distinctuid from nov_visit_20161120 where pv_listen>0);
问题是表nov_visit_20161120没有pv_listen列,但是查询运行得很好。当
languages.language) AS languages, personal.city, payment.before INNER JOIN languages ON languages.uid= personal.uid WHERE personal.uid = 36
返回我的查询如下:因此,如果payment.uid = pe