我试图在两个模型之间建立关系,但是与一个模型的关系总是空的。
我有下面的模型
Profile Model
class Profile extends Model
{
protected $table = 'members';
public function photos(){
return $this->hasMany('App\Models\Photo', 'uid', 'id');
}
}
Photo Model
class Photo extends Model
{
p
现在,我需要类中一个模棱两可类型的成员。这里我要说的是模棱两可,这意味着该成员可以是同一基类的两种或两种以上类型。请看下面的代码。
class Base {
protected:
int m_int;
Base(int i) : m_int(i) {}
};
class Derived1 : Base {...};
class Derived2 : Base {...};
class AnotherClass {
private:
Base m_member; // <- this member
public:
AnotherClass(int se
我的app.php
/*
|--------------------------------------------------------------------------
| Default Authentication Driver
|--------------------------------------------------------------------------
|
| This option controls the authentication driver that will be utilized.
| Thi
我在Laravel寄存器上发现了这个错误
Call to a member function validate() on null
错误只在验证通过时发生,当验证失败时,它会显示返回到寄存器视图的正确错误。我试图在if失败后进行dd,但它没有到达:
protected function validator(array $data){
$req = new Request($data);
//dd($req,$data);
$this->validate($req,
[
'nam
我想将std::make_unique函数声明为我们类的朋友。原因是我想声明构造函数protected,并提供使用unique_ptr创建对象的另一种方法。下面是一个示例代码:
#include <memory>
template <typename T>
class A
{
public:
// Somehow I want to declare make_unique as a friend
friend std::unique_ptr<A<T>> std::make_unique<A<T>>();
我在我的成员模型中创建了验证规则,不需要提供出生日期。但是,当有人填写他们的出生日期时,我希望它是1.格式正确,2.日期不能是将来的日期。
但是,当我填写表格并将出生日期留空时,我仍然收到以下错误:
下面是我的基本Member.php模型:
use Esensi\Model\Model;
class Member extends Model
{
protected $rules = [
'name' => 'required|alpha|min:2|max:255',
'surname'
我想了解隐藏在Java中是如何工作的。因此,让我们假设您有以下代码
public class A{
protected SomeClass member;
public A(SomeClass member){
this.member = member;
}
}
public class B extends A{
protected SomeClass member;
public B(SomeClass member){
super(member);
}
public static void mai
我是这样安装gmpy2的:
yum install gmp-devel
yum install mpfr-devel
yum install libmpc-devel
但请指出以下错误:
src/gmpy_mpc.c:1294: error: ‘gmpy_context’ has no member named ‘real_round’
src/gmpy_mpc.c:1294: error: ‘gmpy_context’ has no member named ‘real_round’
src/gmpy_mpc.c:1294: error: ‘gmpy_context’ has no me
我有一个叫做Entity的基类:
public class Entity
{
public int Id {get;set;}
}
假设我有一个名为Customer的类:
public class Customer : Entity
{
public string Name {get;set;}
}
现在,使用NHibernate 3.3.1中基于代码的约定映射,我尝试了以下方法:
public static class DataHelper
{
private static HbmMapping GetMappings()
{
var mapp
我有以下设置:
@Entity
@IdClass(MemberAttributePk.class)
public class MemberAttribute {
@Id
@ManyToOne @JoinColumn(name="member_id")
protected Member member;
@Id
protected String name;
private String value;
public MemberAttribute() {}
// get & set
}
身份证班:
pub
我有三种型号:Member,Invoice和Payment
下面是Member模型:
class Member extends Model
{
public function invoice()
{
return $this->hasOne(Invoice::class);
}
}
在Invoice模型中:
class Invoice extends Model
{
public function member()
{
return $this->belongsTo(Member::class,
假设我们有class A,B,C,D,其中A是基,B,C是中间的,D是在金刚石模型中导出的。
注意:
class B以私有模式继承虚拟,
class C在保护模式下继承虚拟。
class A
{
public:
int member; // note this member
};
class B :
virtual private A // note private
{
};
class C :
virtual protected A // note protected
{
};
class D :
public B, // doesn't me
我正在使用以下使用std::shared_ptr (C++11)的类的结构:
#include <string>
#include <iostream>
#include <vector>
#include <memory>
//class Member is given by a 3rd party library, CAN'T modify its structure!
class Member {//no instance of this class allowed
public:
Member() {};//sh
我是F#的新手,所以请宽恕我。试图将建模为F#的汽车租赁业务。我喜欢的类型是:
客户
司机
小汽车
VehicleType
RentalAgreement 尚未实现
我的具体问题是,一个F#类可以有一个被歧视的联盟成员吗?汽车应该有一个属性来反映它的is...Compact、轿车、卡车等类型的车辆。下面是我目前的代码..。
namespace DSL2
// a DU
type vehicleType = Truck | Compact | Econ | Sedan
// a record
type Customer = {firstName: string; lastName: st
而不是这样:
class base
{
protected:
base( int value )
: member{value}
{}
int member = 0;
};
class derived_1 : public base
{
public:
derived_1()
: base{ 1 }
{}
};
class derived_2 : public base
{
public:
derived_2()
我有一个分组类,它包含:
class Groups {
protected $_db;
protected $member_id;
protected $group_id,$group_title;
public function __construct($db, $member_id) {
$this->_db = $db;
$this->member_id = $member_id;
}
/**
* Set the group title
*
* @param str $group_id
*
*/
public function set_g