.'";';
$result = mysql_query($query) OR die(mysql_error()); 如果我回显我的$query,我会得到这个。project = "1" 我得到了这个错误: You have an error in your SQL syntax; check the manual that corresponds to your MySQL
我一直在阅读关于mysql_fetch_*方法的文章。这是我从PHP.org网站上学到的。mysql_fetch_array — Fetch a result row as an associative array, a numeric array, or both看起来,mysql_fetch_array包含所有存在于
mysql_fetch_assoc,mysql_