$results = mysql_query('SELECT DISTINCT artist FROM mm_albums WHERE artist LIKE "'. mysql_real_escape_string($_REQUEST['term']) .'%" ORDER BY artist ASC LIMIT 0,10', $dbcon);
if ( $results &&mysql_n
from goods where (name like '%%' or brand '%%' or alias like '%%') and category_id = 1 order by id limit20
Mysql版本5.6.16-log,上面两个sql有没有相同的性能业务背景,用户可以按关键字或类别搜索商品,如果用户不输入<
我的SQL查询是SELECT * FROM chat WHERE to = '$user_id' AND client_id = '001' LIMIT 4。由于某些原因,该查询给出了以下错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQLserver version for the right syntax to use near 'to = '1' AND cl