根据这个,我的理解是我可以在mysql 5.5.6+中运行这样的查询:
set @limit_start=10;
set @limit_offset=10;
select
ID,
AGE,
GENDER
from
PLAYER
limit
@limit_start, @limit_offset;
但是当我像这样运行它时,我会得到一个错误。
mysql> set @limit_start=10;
Query OK, 0 rows affected (0.00 sec)
mysql> set @limit_offset=10;
Query O
下面的脚本只显示第一页,链接到下一页在那里,但不指向任何地方。有人能帮我吗?
$var = @$_GET['q'] ;
$trimmed = trim($var);
$limit = 10;
if ($trimmed == "")
{
echo "<p>What are you looking for?...</p>";
exit;
}
if (!isset($var))
{
echo "<p>We dont seem to have a search paramet
## Keep Radio Button Value after Next/Prev page .. ##
这是给学生在线考试的
if(!isset($_GET['start'])){
$_GET['start'] = "undefined";
}
$start=$_GET['start']; /*To take care global variable if OFF*/
if(!($start > 0)) { /*This variable is set to z
我正在尝试为CentOS 7上的MariaDB版本5.5.60更改max_connections和open_files_limit。因为可能有多个my.cnf文件,所以我使用mysql --help --verbose来获取可能的位置。下面是输出: Default options are read from the following files in the given order:
/etc/mysql/my.cnf /etc/my.cnf ~/.my.cnf Cnf.etc/ mysql /my.cnf不存在,根也不在我的用户目录、/ .my.cnf /或mysql用户目录(一开始就
我正在编写一个小型bash脚本来获取数据库表的随机示例,并通过ssh进行连接。
ssh $SERVER 'mysql -e "SELECT * FROM ${TABLE} WHERE RAND() < ${PROBABILITY} LIMIT ${LIMIT}" -uroot -p ${DATABASE} > temp_dump_file.sql'
我无法解释这些论点。错误是:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL
我想知道从这些sql方法中哪种方法更好(更快);
第一种方法:
public static function getlistusers($limit=88888888888888 ) {
$sql = "SELECT id,name FROM users order by id desc limit 0,$limit";
$st = mysql_query( $sql ) or die(mysql_error());
$list = array();
while ( $row = mysql_fetch_assoc($st) ) {
$picss = new users( $r
我收到了这个错误
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(int) , (int)' at line 2
我在上跟进了这个答案
我得到基和限制作为字符串,我想把它们转换成int。这是我的密码
$category = $_POST['category'];
$base= $_POST['base'];
$l
我写这段代码是为了在每次点击时从数据库表‘community_ post’中删除一个帖子。当我点击按钮,它没有删除它,他得到的网址与do=delete&key=THEID,但它不工作,为什么?有人能帮帮我吗?
// PHP CODE
if($do == "delete" && is_numeric($key)){
$check = mysql_query("SELECT id FROM community_posts WHERE id = '".$key."' LIMIT 1") or di
我在php代码中有以下内容:
$result=mysql_query ("SELECT title, image FROM board order by date limit 15");cq();
我想用sql查询的结果替换15:
SELECT count FROM cat_count
所以我把它放到php中,但是它不起作用:
$cat_count=mysql_query ("SELECT count FROM cat_count");cq();
$result=mysql_query ("SELECT title, image FROM board o
<?php
$s = $_GET["s"];
if($s) {
$hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '1' ORDER BY id DESC LIMIT 0,200") or die(mysql_error());
}else{
$hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '0' ORDER BY id DESC LIMIT 0,20
如何在mysql中查看当前编号,其中....
我的问题是
$aid = 16;
$get_prev_photo = mysql_query("SELECT * FROM photos WHERE album_id='$aid' AND pic_id<'$picid' ORDER BY pic_id LIMIT 1");
$get_next_photo = mysql_query("SELECT * FROM photos WHERE album_id='$aid' AND pic_id>
我正在尝试获取MySQL查询中的变量。
$filter = $_GET['fltr'];
require_once('core/dbconnect.php');
if($filter)
{
$limit = 'LIMIT '. $filter;
}
$lastonline = mysql_query("SELECT * FROM logins ORDER BY time DESC GROUP BY username '$limit'");
现在问题出在我把'$limit‘放在查询中的某个地方。这是行
我在将mysql放入函数showMsg()时遇到了问题。如果mysql没有被函数showMsg()包装,那么它工作得很好,但是当我用函数showMsg()包装它时,它给出了错误消息"Warning: mysql_query():提供的参数不是有效的“。如何将mysql放入php函数中?下面是我的代码:
<?php
function showMsg(){
$query2 = "SELECT id, message, username, datetime FROM messageslive ORDER BY id DESC LIMIT 20
而不是硬编码查询:限制3,我想得到不同的限制号码,每次我按下按钮。
到目前为止,这就是我所得到的:
$region=$_GET["region"];
$number=$_GET["limit"];
$con = mysql_connect('localhost') or die(mysql_error());
mysql_select_db('test') or die(mysql_error());
$sql1="SELECT size,price,member FROM buy WHERE region=
我想知道如何在bash循环中传递*变量。我想在db上运行多个select查询,我想我应该使用bash循环,如下所示:
for query in "select * from filtertype limit 10;" "select * from filter limit 10;"; do echo $query; echo $query | mysql -uroot -ppassword database; done
问题是,*一直在像这样扩展:
[Bash]$ for query in "select * from filtertype limit
我使用follow mysql语句通过php从mysql获取一些信息。
( SELECT *
FROM mytable
WHERE qid NOT IN ({$used['used']})
AND level = 1
ORDER BY RAND()
LIMIT 5)
UNION
( SELECT *
FROM app_mytable _qt
WHERE qid NOT IN ({$used['used']})
AND level = 2
ORDER BY RAND()
LIMIT
我想在我提交表单后,它可以显示命中计数器..但我希望在它达到" 20“之后,它可以返回到zero..bcoz,提交的次数限制是20次,所以它不能超过限制。
我怎么才能让它工作呢?我一直在尝试这段代码...
<?
$limit="20";
$Query_counter=mysql_query("SELECT model FROM inspec");
$Show_counter=mysql_fetch_array($Query_counter);
$show_counter = $show_counter["model"]+1;
if