我正在使用下面的查询来使用left join从两个表中获取多个列的总和。但是mysql显示了“错误代码: 1111.无效使用组函数”的错误,请指出我的错误所在?
SELECT url as Domain,
A.advertiserid as advertiserid,
count(A.salesId) as Impressions,
Sum(IF(A.click1datetime IS NULL,0,1)) AS Clicks,
sum(count(B.order_id)) as Sales,
sum(sum(B.order_amount)) as SalesAmount
我需要一个MySQL不提供的聚合函数。
我希望它符合MySQL的SQL风格(也就是说,不是在C中)。
我该怎么做?我坚持的是创建一个聚合函数-- 文档似乎没有提到这是如何实现的。
需要使用product函数的示例:
mysql> select product(col) as a from `table`;
+------+
| a |
+------+
| 144 |
+------+
1 row in set (0.00 sec)
mysql> select col, product(col) as a from `table` group by col;
+-----
收到以下错误:
Expression #2 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'world.country.Code' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
运行以下查询时:
select countrylanguage.language, country.cod
我的SQL查询是:
SELECT * FROM
(SELECT * FROM transactions) AS T1
PIVOT(SUM(amount) FOR month IN([March], [April], [May])) AS pvt
我的表格如下:
id payee amount month
1 Tom 90 March
3 Tom 66 April
4 Tom 89 May
10 Jasmine 125 April
11 Nancy
我想做一个查询,其中我有每个设备的总数:数量*成本。 现在,我想要执行一个MySQL查询,其中我创建了一个执行以下操作的临时列: Total - Total of Totals
80 - 80
90 - 170
100 - 270 现在我有一个这样的代码: Select total
from equipment
UNION ALL
select sum(total) from equipment; 它给出了总数下面的总数。我想把它分开,然后在它旁边按顺序做。
我需要你在access db方面的帮助
我有一张这样的桌子
ID CLASS LESSON
1 7 MATH
2 7 CHEM
3 8 GEOM
4 8 MATH
5 8 CHEM
6 9 MATH
...
在mysql sql命令中,如下所示
select CLASS, LESSON
from t_class
group by LESSON
返回结果如下
ID CLASS LESSON
1 7
我想知道如何排除mysql组,我在这里做了一段时间的研究,但只是不让它正确。
我试过了
SELECT * FROM booking GROUP BY BookingId HAVING Status!="Cancellation"
显然不起作用。
示例数据库如下所示:
+----+-----------+--------------+
| id | BookingId | Status |
+----+-----------+--------------+
| 1 | 1 | Booked |
| 2 | 1 | Can
我们知道如何做简单的MySQL算法,例如:
mysql> select 10-7 as 'result';
+--------+
| result |
+--------+
| 3 |
+--------+
但是,如果"10“和"7”本身就是MySQL select查询的结果,我们如何计算?-例如:
select x.balance from (
select sum(amount) as 'balance'
from table
where date between "2019-06-01" an
如何才能使此查询起作用:
SELECT column1.....,SUM(Hits) AS Hits
FROM table
WHERE SUM(Hits) > 100
GROUP BY column1.....
问题是where子句,mysql显示错误:
Error Code : 1111
Invalid use of group function
我尝试将查询更改为:
SELECT column1.....,SUM(Hits) AS Hits
FROM table
WHERE Hits > 100
GROUP BY column1..
我有一个MySQL表,其中的行包含重复的text值('a'和'c'):
+------+-----+
| text | num |
+------+-----+
| a | 10 |
| b | 10 |
| c | 10 |
| d | 10 |
| c | 5 |
| z | 10 |
| a | 6 |
+------+-----+
因此,我想更新这些行,将num的值相加。在此之后,该表应该如下所示:
+------+-----+
| text | num |
+------+-----+
| a
我有两个MYSQL查询,我试图合并成一个,这是第一个-
SELECT
`Your_Name` as agentname,
sum(`Sale_Amount`) as todaysales,
COUNT(*) as NoSales
FROM mp_wp_sales_tracking
WHERE `created` BETWEEN CURDATE() AND NOW()
GROUP BY agentname
第二个查询与前一天的查询相同。
SELECT
`Your_Name` as agentname,
sum(`Sale_Amount`) as yesterday
你好,我试图总结两个mysql结果的结果。
这是我的代码,不起作用。
SELECT
a.* ,
b.* ,
SUM(b.price) as price,
SUM(b.tax) as tax,
price + tax as price_tax --> error
FROM (SELECT name , item_id
FROM items)a
LEFT JOIN (SELECT item_id , price , tax
FROM bank
)b
ON a.item_id = b.item_id
我不是MySql方面的专家,我想做的是,创建一个查询将按月和年份返回正在运行的总计:
SELECT DISTINCT
date_format(t.created_at, "%M") AS month,
date_format(t.created_at, "%Y") AS year,
SUM(COUNT(*)) over (order by MONTH(created_at) ) as cumulative
FROM team t
GROUP BY YEAR(created_at), MONTH(created_at)
ORDER BY
我想要写一个sql查询,如果特定列的和为零,那么结果将被检索。我尝试了如下:(我只写了检查部分,因为错误只会出现在这个部分)。
query=.... WHERE SUM(column1)='0'
coumn1有整数数据类型。我得到了以下错误:
java.sql.SQLException: Invalid use of group function
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:946)
任何帮助都是非常感谢的。谢谢。