$avg_pgt = mysql_query("SELECT avg(convert(custom_var_v1,unsigned)),min(convert(custom_var_v1,unsigned)), max(convert(custom_var_v1,unsigned) FROM `table_name` WHERE server_time BETWEEN '$date 00:00:00' AND '$date 23:59:59'");
$row_all = mysql_fetch_array($av
因此,我有一个比较长的查询,如下所示:
SELECT (
(CASE Methanethiol
WHEN -1 THEN 0
ELSE Methanethiol
END)
+
...
+
(CASE nHeptanethiol
WHEN -1 THEN 0
ELSE nHeptanethiol
END)
)
FROM condensates.mercaptans
WHERE (
(CASE Methanethiol
WHEN -1 THEN 0
我有一个MySQL声明:
SELECT name, ((AVG (q1) + AVG(q2) + AVG(q3) / 3) AS Average
FROM tresults GROUP BY name ORDER BY name;
我还有另一个MySQL语句:
SELECT name, ((AVG (q1) + AVG(q2) + AVG(q3) / 3) AS Average
FROM tresults WHERE q35 = 1 GROUP BY name ORDER BY name;
我尝试过使用子查询,但由于它返回多行,下面的代码无法工作:
SELECT name, ((AVG (
我正在寻找一种有效的方法来为MySQL表中的每一行分配Z分数(也称为标准分数)。
Z = Z-Score
X = Actual value
μ = Mean value
σ = Standard Deviation
我试过了:
SELECT pTime,(M1-AVG(M1))/STD(M1),
(M2-AVG(M2))/STD(M2),
(M3-AVG(M3))/STD(M3),
(M4-AVG(M4))/STD(M4)
FROM mergebuys;
但最终只有1行。
当只需要计算一次子查询时,使用子
如何使用ROW_NUMBER()函数(必选)在Mysql表格显示中显示行号? mysql> select * from work;
+------+-----------+
| name | work_days |
+------+-----------+
| john | 5 |
| jane | 7 |
| jane | 2 |
| john | 3 |
+------+-----------+
4 rows in set (0.01 sec) 不使用ROW_NUMBER(): mysql> SELECT nam
我正在尝试使用PHP中的以下查询更新表'notes'中的行。
$xyz = mysql_query("Select AVG(x) as AVG_X, AVG(y) as AVG_Y, AVG(z) as AVG_Z FROM `notes_two` where id=".$id);//I am selecting average value of (x,y,x) from another table notes_two
$rowxyz = mysql_fetch_row($xyz);
// Saving the position a
我已经处理过这个查询:
SELECT round(avg(total_kpi),2) as avg_kpi,
case when avg(total_kpi) < 3 then 'NEG'
when avg(total_kpi)>3 then 'POS' end as kpi,
count(gender) as gender,
gender,
round(avg(locacion),2) as avg_locacion,
round(avg(tiempo),2) as avg_tiempo,
round(avg(serv
在MySQL数据库上使用此查询5.5.62版
SELECT
COUNT( CASE WHEN MONTH ( tData ) = 1 THEN 'Jan' END ) Jan,
COUNT( CASE WHEN MONTH ( tData ) = 2 THEN 'Feb' END ) Feb,
COUNT( CASE WHEN MONTH ( tData ) = 3 THEN 'Mar' END ) Mar,
tname,
AVG( DATEDIFF( COALESCE ( tClosed, tOpen )
就像MIN()和AVG()一样,有时我需要整数值的最常见的出现值(AKA,模式)。这可以这样获得:
SELECT column, COUNT(*) AS x
FROM table
GROUP BY column
ORDER BY x DESC
LIMIT 1
这可真是一口大口。我真的很想用它,比如:MODE()
SELECT AVG(`sTemperature`), MODE(`sSwitch`), MODE(`sDoor`)
FROM `stats`;
有办法使上面的查询对整数有效吗?对于布尔人来说,我认为ROUND(AVG())是好的。
可以在MySQL DB中定义函数,但它们能像M
我有两个mysql表 票数: user
movieid
starCount 电影: id
title
description 我想为表中的每一部电影获取id,title,description,avg(starCount)。 我试过了: select id,title,description,avg(starCount)
from movies
join votes on movies.id=votes.movieid
我有一个mysql表:
CREATE TABLE person (id INT(6) AUTO_INCREMENT PRIMARY KEY,name VARCHAR(30) NOT NULL,age int(4) NOT NULL);
我运行这些插入:插入到person值(null,'one',42);插入到person值(null,‘2’,49);插入到person值(null,‘3’,16);
跑步:
select avg(age) from person;
给我"35.6“
然后我在狮身人面像中索引这些表。现在,我希望在Sphinx中运行与我在MySQL中运
我有一个MySQL查询:
select Region,
CONCAT('$', FORMAT(AVG(sales), 0)) as 'Average_Sales_by_Region',
count(*) as '# of Dist in state'
from dist, Regions_US
where dist.state=Regions_US.State
group by Region ORDER BY AVG(sales) DESC;
下面是上面MySQL查询的输出:
+--------------------+------------
我有以下MySQL语句,它可以完成我想要的操作:
SELECT scores.score, registrations.parade, AVG(scores.score) as result
FROM scores
JOIN registrations ON scores.registrationId=registrations.id
where registrations.parade=1
GROUP BY scores.registrationId
ORDER BY result DESC
基本上,对于sqlalchemy,我想我会从:
db.session.query(Scores, f
下面是当我在group by语句中使用聚合列时抛出错误的sql查询。请建议如何在MySQL中有效地执行此操作。
select
CASE
WHEN avg(sm.pace)<0.30 THEN 'Ineligible'
WHEN avg(sm.pace)>=0.30 AND avg(sm.pace)<0.40 THEN 'Tier1'
WHEN avg(sm.pace)>=0.40 AND avg(sm.pace)<0.50 THEN 'Tier2'
WHEN avg(sm.pace)&g
我试图从表的评级列中获取平均值,然后按降序在HTML表中为每个不同的div_id及其平均评分显示一行。我知道这应该很容易,但我很难搞清楚。任何帮助都将不胜感激。
<?php
mysql_connect($db_server, $db_username, $db_password) or die(mysql_error());
mysql_select_db($db_database) or die(mysql_error());
$result = mysql_query("SELECT * FROM ratings") or die(mysql_error());
我是MySQL新手,正在尝试将在Microsoft SQL Server中工作的代码转换为MySQL。下面的SELECT语句在MySQL中有效,但在INSERT INTO中无效。对于带有MySQL的聚合语句的INSERT INTO,是否有不同的格式? -- Adding data to the Health Data Baseline table
INSERT INTO Health_Data_Baseline (
Total_Sleep_Duration_Baseline
,Body_Weight_Baseline
,Body_Mass_Index_Baselin
在MySQL中,我有一张这样的桌子:
id | date | num | avg
我已经发现,我可以将它用于列的行,到目前为止,它是有效的:
SELECT
CONCAT(id, '-', date),
MAX(IF(`num` = 0, avg, NULL)) num0
FROM table
GROUP BY
id,
date;
问题是我有4000 'num‘值(值是0到4000之间的整数),我不想手动编写4000 MAX语句。不管怎样,我能在里面放个循环吗?理想情况下,我希望有4030个专栏..。
编辑:
我编辑了我的帖子,
我最近写了一个网站,它使用mysql作为数据库,现在我想将我的数据库改为sql服务器,但我的查询有太多问题……有人告诉我,mysql和sql server查询非常相似,但我似乎搞不清楚这一点!
SELECT
datos.NumEstacion, MAX(datos.Fecha), datos.NumFuncion, datos.Valor, parametros_mi.nombre AS NombreParametro, funciones_mi.Nombre AS NombreFunction
FROM
(datos JOIN parametros_mi ON datos
我有一个返回值或空白页的PHP函数,我想用JS检查它。
PHP:
function get_CTDIvolAVG($min, $max) {
$query = "SELECT AVG(ct.ctdivol_mGy) FROM exam
INNER JOIN ct on exam.examID = ct.examID AND ct.ctdivol_mGy > 0
WHERE exam.modality = 'CT'
AND (unix_timestamp(exam.da
我试图用Redshift编写下面的MYSQL代码,但是Redshift中不存在TO_DAYS()。我也试过年龄,但那不管用。
SELECT
AVG(CASE WHEN s_status = 'finish' THEN (TO_DAYS(date1) - TO_DAYS(date2)) ELSE NULL
END) AS avg_time,
SUM(CASE WHEN s_status = 'finish' AND (TO_DAYS(date1) - TO_DAYS(date2))<=7 THEN 1
我试图获得过去两个月的平均值,但不是基于CURDATE()/NOW()。它将取决于用户在应用程序中查看的月份:
例:如果我看五月,我会想要四月和三月的平均数。如果我看二月份,我会想要一月和十二月的平均数(前一年的)。
我有一个函数,它接受用户所在页面的月份和年份(它也接受emp_id,但这与这个问题无关)。
public function getProtectedAmt($month,$year,$id){
$query = "SELECT avg(total_payout) as avg_payout FROM saved_plan_data WHERE emp_id = '
我无法在Oracle上执行此代码,错误显示:
"ORA-00979:非按表达式分组“
但是,我能够在MySQL上成功地运行它。
这是怎么发生的?
SELECT CONCAT(i.lname, i.fname) AS inst_name,
CONCAT(s.lname, s.fname) AS stu_name,
t.avg_grade AS stu_avg_grade
FROM(
SELECT instructor_id, student_id, AVG(grade) as avg_grade, RANK() OVER
我最近才从Rails 2.3.5升级到Rails 3.2.7,并且在我的一些查询中注意到一些性能下降。我知道Rails 3 ActiveRecord在某些情况下比Rails 2.3.5慢,但是我的基准测试让我感到惊讶,我只是想确保我没有遗漏任何东西。
作为基准测试,我运行了以下查询,这在我的应用程序中非常流行
SELECT SQL_NO_CACHE table_name.* FROM table_name WHERE ((string_col = 'value') AND (int_col1 BETWEEN 5 AND 30)) ORDER BY int_col2 DESC L
下面的语句给出的结果没有任何错误,
select
title as 'unreviewed series',
rating from series
left join reviews
on series.id= reviews.series_id
where rating is null;
但是,以下是一个错误:
select title as 'unreviewed series',
ifnull(avg(rating), null) as 'Average Rating'
from series
left join
在MySQL中,我有一个查询/表
SELECT *
FROM
(
SELECT
id,
(SELECT MY_FUNCTION(id)) AS rating -- Function returns a float
FROM my_table
WHERE
/* Very long WHERE */
) AS ratings
id rating
---------- -------------
1 1.00
2 2.00
3
我需要帮助才能将嵌套查询的结果分配到数组中。这是一个场景:
$Date_Collection = mysql_query("SELECT DISTINCT Date FROM TblDate");
while($date = mysql_fetch_array($Date_Collection)) // Loop through all the dates
{
$var_date = $date['Date'];
$result = mysql_query("select min(Speed) as Min_spd, max (Spee