环境:
Python 3.7
我有一个装满Mysql表格的烧瓶网页表单。
我知道这个错误:
TypeError: object of type 'int' has no len()
在线路上:
if form.validate_on_submit():
我的routes.py
我检查了模型和类形式,但我没有看到任何问题。我在代码中没有对任何整数使用"len“函数。
我在Stackoverflow中看到了一些类似的问题,但是这个解决方案不适合我的字段。
我怀疑布尔字段-- enable、smartphone_allowed和computer_allowed --是这个问题
这里我有一些php代码,用来显示来自一个名为“Collection”的字段的唯一/disctinct值。我已成功地连接到其他地方的数据库。当这个php代码执行时,浏览器给我一个“警告: mysql_fetch_array():提供的参数不是第20行mypage.php中的有效MySQL结果资源”。
$id = isset($_GET['id'])?(int)$_GET['id']:0; // if $_GET['id'] exists, return it as an integer, otherwise use a senti
MySQL 5.1不允许我在limit中使用声明变量。我尝试了所有的替代方法,但都不起作用,而且我无法更新MYSQL版本。是否有其他方法可以在MySql 5.1中运行此查询而不出错。我在MySql 5.6和更高版本中尝试了同样的查询,它工作得很好。 delimiter $$
CREATE event `cleaner` ON schedule every 7 day enable do
BEGIN
DECLARE `logCount` int(11);
SET `logCount` = (Select count(*) from `eventlogs`) - 5000;
DELETE FRO
我有问题删除记录在innodb (表有一些项目100k记录或1mln记录) Innodb有文件每个表我不知道为什么会发生这种情况。我总是可以删除一些记录,然后我看到“表已满”...几秒钟后,我可以删除更多的记录。
mysql> DELETE from xxxx WHERE id > 1413139758 AND id <= 1413819239 LIMIT 10000;
Query OK, 10000 rows affected (0.30 sec)
mysql> DELETE from xxxx WHERE id > 1413139758 AND id <
我的代码:
selectQ ="""SELECT * FROM %s WHERE %s = %%s order by RAND() limit %s""" % (self.table,self.columnSpecName,limit),
self.db.execute(str(selectQ),(idKey))
我得到了一个例外:mysql_exceptions.ProgrammingError: (1064, "You have an error in your SQL syntax; check the manual that c
我有以下声明
$result = mysql_query("SELECT * from rests ORDER BY name asc WHERE flag = '1' LIMIT 0 , 20");
我收到以下错误
Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE flag = '1
public function Read($Table, $Fields, $Condition, $Orderby, $Limit) {
$Query = "SELECT $Fields FROM $Table";
if ($Condition != null) {
$Query .= " WHERE " . $Condition;
}
if ($Orderby != null) {
$Query .= " ORDER BY " . $Orderby;
}
if (
Mysql/php
我可以让分页起作用。但在第二页,它只列出了三个结果。页面的其余部分不会显示任何结果。我做错了什么?
//$result=mysql_query("select count(*) from users WHERE level > 14");
$result=mysql_query("select count(*) from users WHERE level > 14 ORDER BY uid ASC LIMIT 200");
//$result=mysql_query("SELECT *, COUNT(level) FR
我正在尝试使用从数据库中检索数据,但将其限制为每个视图一定数量的项目。但是我得到了上面提到的错误。我创建了以下函数来检索数据:
//function to display jobs
function display_jobs($start,$per_page)
{
//Select the data from the database, but limit it to the number of item per page
$query = "SELECT a.`title`,
a.`vacancyid`,
我有一个MYSQL数据库运行一些测试,这是从网页上获取表‘结果’的值。它包含一些行和列。
当我尝试的时候:
select * from results limit 10;
它显示了来自某个表的数据库的前10行。
基本上,我想删除这些行。当我尝试的时候:
delete from results where (select * from results limit 10) ;
它不会删除这些行,并会询问:
delete from results where (select * from results limit 10) ;
我也试着去做:
mysql> delete * from resu
这是我使用的代码
$Last_Video = $db->fetch_all('
SELECT VID, thumb
FROM video
WHERE VID IN (
SELECT VID
FROM video
WHERE title LIKE "%'.$Channel['name'].'%"
ORDER BY viewtime DESC
LIMIT 5)
ORDER BY RAND()
L
DELETE
LIB, REL
FROM
test_library_song LIB
INNER JOIN
test_relation REL
ON
LIB.book_id = REL.book_id
WHERE
REL.user_id = '1'
AND
REL.book_id = '400'
LIMIT 1
它抛出一个错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server versi
我可以在MySQL插入查询上使用LIMIT 2吗?例如:
INSERT INTO MyTable
(user_name,password)
VALUES
(john,366543),
(sam,654654)
LIMIT 2
我试过了,它说
`#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 2' at line 1
有人能帮我转换成MYSQL,因为在MYSQL中不支持IN。我应该使用内连接吗?但是怎么做呢? DELETE from SSLDOMAINS_logstable where id IN (SELECT id from SSLDOMAINS_logstable order by id asc limit 50)
有人能告诉我这个mysql查询有什么问题吗?
$p = mysql_query("SELECT name,subname FROM brands GROUP BY name WHERE
having count(*) > 10 ORDER BY RAND() LIMIT 1")or die(mysql_error());
上面写着:
您的SQL语法出现了错误;请检查与您的MySQL服务器版本相对应的手册,以便在第1行使用接近于“由RAND()限制1顺序计数(*)> 10次”的正确语法。
要将大量的CSV文件插入到MySQL中,就有LOAD DATA INFILE,但是是否有类似的命令来删除存储在大量CSV文件中的密钥的大量条目?
如果没有,您认为最快的操作方法是什么?
编辑:另外,您认为这2种方法中哪一种是最有效的:
多次删除
DELETE FROM myTable WHERE mykey=1 LIMIT 1;
DELETE FROM myTable WHERE mykey=2 LIMIT 1;
...
DELETE FROM myTable WHERE mykey=300000 LIMIT 1;
或批删除
DELETE FROM myTable WHERE mykey IN
我有:
mysql_query("DELETE FROM mytable ORDER BY id DESC LIMIT 3, 999999999;")
or die(mysql_error());
但它似乎不喜欢它。我希望保留最近的三行,并删除其他所有内容。有什么想法?
后续行动-感谢你的同时的金克斯!
我尝试了这段代码,得到了这个版本错误:
This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
我检查了我的主机,我有: MySQL版本5.5.3
我的问题是当我试图获取大量记录的咨询返回计数时引起的(示例500.000):
示例:
$limit = ' LIMIT 0,30';
$ResultQuery = mysql_query("
SELECT id, name, description, date
FROM products
WHERE name
LIKE 'dog%'".$limit);
$CountQuery = mysql_query("
SELECT COUNT(id)
FROM products
W
我的MySQL查询
(SELECT * FROM names WHERE Rate = 75 ORDER BY RAND() LIMIT 1)
UNION
(SELECT * FROM names WHERE Rate = 75 ORDER BY RAND() LIMIT 1)
UNION
(SELECT * FROM names WHERE Rate = 35 ORDER BY RAND() LIMIT 1);
它应该给我这样的东西
+----+-----+------+
| id | Rate| num |
+----+-----+------+
| id | 75 | 9
我正在为我的网站编写一个新的搜索脚本,其中包含多个字典。首先,让我向您展示有问题的代码片段,然后解释...
$sql = mysql_query("SELECT * FROM $tbl_name WHERE $field = '%$trimmed%' ORDER BY $field ".$sort." LIMIT ".$limits.", $max")or die(mysql_error());
$count = mysql_result(mysql_query("SELECT COUNT($field) FROM $tb
我的while循环跳过该元素。寻找了类似的问题,但仍然无法理解。请开导我一下。tnx!
$query = "SELECT userid, COUNT(content) as x_count
FROM x GROUP BY userid ORDER BY x_count DESC
LIMIT 5";
$result = mysql_query($query) or die("Error in query:".mysql_error());
根据这个,我的理解是我可以在mysql 5.5.6+中运行这样的查询:
set @limit_start=10;
set @limit_offset=10;
select
ID,
AGE,
GENDER
from
PLAYER
limit
@limit_start, @limit_offset;
但是当我像这样运行它时,我会得到一个错误。
mysql> set @limit_start=10;
Query OK, 0 rows affected (0.00 sec)
mysql> set @limit_offset=10;
Query O
大家好,我对mysql like和limit命令有问题,当它们一起使用时,它们返回0 null我在我的php中尝试了一下,然后我去phpmyadmin内部测试它,我得到了相同的结果,这里是代码
//mysql
SELECT * FROM `items` WHERE name like '%php%' LIMIT 9,9; //this return null
SELECT * FROM `items` WHERE name like '%php%' LIMIT 9 OFFSET 9; //this return null
SELECT * FROM `i
为了获得表的最高值和最小值,正确的(MySql)查询是什么?我得到了这一点,但这是错误的:
SELECT * FROM temperaturs ASC LIMT 3 UNION SELECT * from temperaturs ORDER BY `Temperatur_Celsius` DESC LIMIT 3;
这也是错误的:
SELECT * FROM tabelle_name ORDER BY spalte1 DESC LIMIT k UNION SELECT * FROM tabelle_name ORDER BY spalte1 ASC LIMIT k
为什么我不能运行这个MySQL命令?
SELECT *
FROM users
WHERE
id = 1 OR
id BETWEEN 2 AND 8
GROUP BY
username ASC
ORDER BY
username ASC
LIMIT 5
有人能解释一下吗?
我收到以下错误:
ERROR 1064 (42000): You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the right
synt