在MYSQL中有没有其他方法来生成随机排序的sequence_no?我有一张桌子:验证码
SET @a:= 1;
SELECT @a:=@a+1 as sequence_no,captcha_id, captcha_name
FROM captcha,(SELECT @a:= 0) AS a
ORDER BY RAND()
我的预期输出:
sequence_no | captcha_id | captcha_name
----------------------------------------
01 | 11 | name1
02 |
我的菜单有以下PHP代码,它可以选择MySQL中的所有链接和名称:
<?php
$url = '';
//select all the top row items
$sql="SELECT * from website_menu where parent_top = '' and parent = '' order by menu_order ASC ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($r
我有一个PHP代码,它列出了表中的行:
$sql="SELECT * from pages order by menu_order ASC ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<a href="edit_page.php?pagename='.$result["pagename"].'">'.$resu
我在堆栈溢出和另一个编码示例站点中看到了本主题讨论的内容。但我找不到任何成熟的解决方案,有人修复这个错误吗?
错误信息:
ERROR:root:Can't connect to to MySQL server with error: (pymysql.err.InternalError) Packet sequence number wrong - got 1 expected 0
ERROR:root:Can't connect to to MySQL server with error: (pymysql.err.InternalError) Packet sequence
我在PHP中运行这个SQL查询:
$sql="SELECT * FROM customer
JOIN contacts ON (contacts.company_sequence = customer.sequence)
WHERE customer.resellerid = '".$_POST["rid"]."'
AND contacts.email = '".$email."'
AND contacts.password = '
我试图在MySQL中执行PL/SQL语句。但是,当我试图创建一个表时,它会显示一个语法错误。我得到以下错误
CREATE TABLE supplier(supid NUMBER(5) PRIMARY KEY, suppname VARCHAR2(15));
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'NUMBER(5) PR
我的MySQL 4.1Windows服务不时会崩溃,日志中有以下几行:
091218 9:31:25 InnoDB: Database was not shut down normally!
InnoDB: Starting crash recovery.
InnoDB: Reading tablespace information from the .ibd files...
InnoDB: Restoring possible half-written data pages from the doublewrite
InnoDB: buffer...
091218 9:31:33
我在PHP中有一个while循环,我需要在表的一个列中找到最低的数字。
我试过这样做:
$sql="SELECT * from pages order by menu_order ASC ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<a href="edit_page.php?pagename='.$result["pagename"].'">'.$
我试图以该形式显示MySQL查询结果
标题1标题2 Title3.
使用此查询:
SELECT title as titre1 FROM sequence WHERE ID_sequence = 1 UNION SELECT title as titre2 from sequence WHERE ID_sequence = 2 UNION SELECT title as titre3 FROM sequence WHERE ID_sequence = 3
但是显示在此表单中的结果
具有不同行的标题1 (标题1、2和3)。
有什么可以帮忙的吗谢谢!
我用的是节点-mysql。以下代码取自
var http = require('http');
var mysql = require('mysql');
var connection = mysql.createConnection({
host : 'localhost',
port : 3306,
database: 'aaa',
user : 'root',
password : 'z'
});
http.createServer(function(req, res)
在MySQL中,可以很容易地完成以下操作
set @var= (select value from my_sequence);
insert into new_table (id, name)
select @var := @var + 1, name from old_table;
但是,我无法找到在Server中执行相同操作的方法。有可能吗?有什么可供选择的?
我尝试在我的数据库中逐个字符地将一行与另一行进行比较,结果是给出最适合给定数据的id。例如,我的数据库中有一个AAA序列的用户David,我想将它与我给出的ABA序列进行比较,因此我希望获得匹配的百分比(在本例中为66.6%),到目前为止,我已经完成了,但不知道如何继续:
$uname = $_POST['sequence'];
$query = "SELECT name FROM dna WHERE sequence = '$uname'";
$result = mysql_query($query);
while($row = mysql