因此,我使用CONCAT将两个字符串组合在一起,并希望通过在现有字符串的末尾添加一个新字符串来更新数据库中的文本字段。// This code works great. will add "EXTRA" at end of the feed.$insert = ("update $username set feed = CONCAT(feed, 'EXTRA')");
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"Warning: Using a password on the command line interface can be insecure.?ERROR 1031 (HY000) at line 12943: Table storage engine for 'ims_ewei_shop_abonus_billo' doesn't have this option?dumper err?"("-17")
我有下面列出的3个独立的MySQL查询,有没有办法将它们组合在一起,这样我就可以得到相同的输出,而只需要调用一次数据库(而不是3个) <?id,cat,extra1,bigimage FROM pp_photos WHERE extra1 = '120' ORDER BY rand() LIMIT 1" ) or die(mysql_errorid,cat,extra1,bigimage FROM pp_photos WHERE <e